Ask question

Ask question

All categories

iogann1982 [59]

2 years ago

12

Bằng lý luận và thực tiễn, anh (chị) hãy làm sáng tỏ nhận định: “Tâm lý người là sản phẩm của hoạt động và giao tiếp”, từ đó rút

ra những kết luận cần thiết đối với bản thân.

1 answer:

Ronch [10]2 years ago

3 0

the awnser is yes because when I did this assignment I got an A

You might be interested in

An induced charge is when charged particles can be attracted to neutral objects.<br> True or false?

Sindrei [870]

Answer:

the answer is true Induction charging is a method used to charge an object without actually touching the object to any other charged object.

Explanation:

5 0

3 years ago

25 points whoever actually ANSWERS the question CORRECTLY

guapka [62]

Answer:

D. The frequency is not affected as the volume of sound increases

Explanation:

Volume of the sound is defined by the amplitude of the wave or how loud a sound is whereas Frequency is basically the pitch of the sound and is inversely proportional to the wavelength . Increasing frequency will increase the pitch of the sound without affecting it's volume.

5 0

3 years ago

Alkali metals _____.

Lyrx [107]

I think the answer is C

7 0

3 years ago

Can someone help me with the motion maps, I don't understand what I am supposed to write in the description or how to draw the a

Ugo [173]

Answer:

i d k

Explanation:

7 0

2 years ago

Constant Acceleration Kinematics: Car A is traveling at 22.0 m/s and car B at 29.0 m/s. Car A is 300 m behind car B when the dri

Ainat [17]

Answer:

The taken is $t_A = 19.0 \ s$

Explanation:

Frm the question we are told that

The speed of car A is $v_A = 22 \ m/s$

The speed of car B is $v_B = 29.0 \ m/s$

The distance of car B from A is $d = 300 \ m$

The acceleration of car A is $a_A = 2.40 \ m/s^2$

For A to overtake B

The distance traveled by car B = The distance traveled by car A - 300m

Now the this distance traveled by car B before it is overtaken by A is

$d = v_B * t_A$

Where $t_B$ is the time taken by car B

Now this can also be represented as using equation of motion as

$d = v_A t_A + \frac{1}{2}a_A t_A^2 - 300$

Now substituting values

$d = 22t_A + \frac{1}{2} (2.40)^2 t_A^2 - 300$

Equating the both d

$v_B * t_A = 22t_A + \frac{1}{2} (2.40)^2 t_A^2 - 300$

substituting values

$29 * t_A = 22t_A + \frac{1}{2} (2.40)^2 t_A^2 - 300$

$7 t_A = \frac{1}{2} (2.40)^2 t_A^2 - 300$

$7 t_A =1.2 t_A^2 - 300$

$1.2 t_A^2 - 7 t_A - 300 = 0$

Solving this using quadratic formula we have that

$t_A = 19.0 \ s$

7 0

3 years ago