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iogann1982 [59]

2 years ago

12

Bằng lý luận và thực tiễn, anh (chị) hãy làm sáng tỏ nhận định: “Tâm lý người là sản phẩm của hoạt động và giao tiếp”, từ đó rút

ra những kết luận cần thiết đối với bản thân.

1 answer:

Ronch [10]2 years ago

3 0

the awnser is yes because when I did this assignment I got an A

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Water is flowing in a pipe with a circular cross section but with varying cross-sectional area, and at all points the water comp

slamgirl [31]

(a) 5.66 m/s

The flow rate of the water in the pipe is given by

$Q=Av$

where

Q is the flow rate

A is the cross-sectional area of the pipe

v is the speed of the water

Here we have

$Q=1.20 m^3/s$

the radius of the pipe is

r = 0.260 m

So the cross-sectional area is

$A=\pi r^2 = \pi (0.260 m)^2=0.212 m^2$

So we can re-arrange the equation to find the speed of the water:

$v=\frac{Q}{A}=\frac{1.20 m^3/s}{0.212 m^2}=5.66 m/s$

(b) 0.326 m

The flow rate along the pipe is conserved, so we can write:

$Q_1 = Q_2\\A_1 v_1 = A_2 v_2$

where we have

$A_1 = 0.212 m^2\\v_1 = 5.66 m/s\\v_2 = 3.60 m/s$

and where $A_2$ is the cross-sectional area of the pipe at the second point.

Solving for A2,

$A_2 = \frac{A_1 v_1}{v_2}=\frac{(0.212 m^2)(5.66 m/s)}{3.60 m/s}=0.333 m^2$

And finally we can find the radius of the pipe at that point:

$A_2 = \pi r_2^2\\r_2 = \sqrt{\frac{A_2}{\pi}}=\sqrt{\frac{0.333 m^2}{\pi}}=0.326 m$

6 0

3 years ago

I need help someone help me

GaryK [48]

what do you need , i mean your help , let me see if i can help

5 0

3 years ago

During low-intensity activity, your body obtains most of its energy from

Gemiola [76]

Carbohydrates, in cellular respiration.

3 0

2 years ago

Who is Isaac Newton?<br><br>Take the points, Im leaving Brainly..

icang [17]

Answer: English

. mathematician

. physicist

. astronomer

. theologian

. author

Explanation:

Take the points, Im leaving Brainly.. Why?!

8 0

2 years ago

If a 0.50-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 3.7 N for a distance of 6

mel-nik [20]

The block's velocity is determined as 10.03 m/s.

<u>Explanation:</u>

According to work energy theorem, the work done on an object is equal to the change in kinetic energy of the object.

So, work done = Kinetic energy

$\text {Force } \times \text { displacement }=\frac{1}{2} \times m \times v^{2}$

Thus, the velocity can be determined as

$\text {velocity}=\sqrt{\frac{2 \times \text {Force} \times \text {displacement}}{m}}$

$\text {velocity}=\sqrt{\frac{2 \times 3.7 \times 6.8}{0.50}}=\sqrt{\frac{50.32}{0.50}}=\sqrt{100.64}$

Velocity = 10.03 m/s.

So the block's velocity is determined as 10.03 m/s.

5 0

3 years ago