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3 years ago

How many Hydrogen (H) Atoms are in Methylene?

Chemistry

2 answers:

Bas_tet [7]3 years ago

6 0

Answer:

FOUR HYDROGEN ATOMS

Explanation:

Two C atoms, four H atoms, and two O atoms can also be arranged to form a methyl formate, which is used in manufacturing, as an insecticide, and for quick-drying finishes. Methyl formate molecules have one of the oxygen atoms between the two carbon atoms, differing from the arrangement in acetic acid molecules.

Temka [501]3 years ago

5 0

The Methylene group has 2 hydrogen. -CH2

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mr_godi [17]

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Ionic (transfer of electrons takes place).

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4 years ago

How many sucrose molecules will be in 250 grams

sasho [114]

<h2>Answer:</h2>

We will need to know Avogadro's number and the molar mass of sucrose for this problem to do dimensional analysis.

Avogadro's number: 6.022 × 10²³ molecules
Molar mass of sucrose: 342.2965 g/mol

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There are 4.398 sucrose molecules in 250 grams of sucrose.

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3 years ago

The greenhouse effect is occurring because Group of answer choices the ozone layer is being depleted by carbon dioxide the amoun

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2 years ago

For the following reaction, 7.53 grams of benzene (C6H6) are allowed to react with 8.33 grams of oxygen gas. benzene (C6H6) (l)

juin [17]

Answer:

The maximum amount of CO2 that can be formed is 9.15 grams CO2

O2 is the limiting reactant

There will remain 4.82 grams of benzene

Explanation:

Step 1: Data given

Mass of benzene = 7.53 grams

Mass of oxygen gas = 8.33 grams

Molar mass of benzene = 78.11 g/mol

Molar mass oxygen gas = 32.00 g/mol

Step 2: The balanced equation

2C6H6 + 15O2 → 12CO2 + 6H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles C6H6 = 7.53 grams / 78.11 g/mol

Moles C6H6 = 0.0964 moles

Moles O2 = 8.33 grams / 32.00 g/mol

Moles O2 = 0.2603 moles

Step 4: Calculate the limiting reactant

For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.2603 moles). Benzene is in excess. there will react 2/15 * 0.2603 = 0.0347 moles

There will remain 0.0964 - 0.0347 = 0.0617 moles benzene

This is 0.0617 moles * 78.11 g/mol = 4.82 grams benzene

Step 5: Calculate moles CO2

For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

For 0.2603 moles O2 we'll have 12/15 * 0.2603 = 0.208 moles CO2

Step 6: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 0.208 moles * 44.01 g/mol

Mass CO2 = 9.15 grams

4 0

4 years ago

How many Hydrogen (H) Atoms are in Methylene?​

How many Hydrogen (H) Atoms are in Methylene?