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3 years ago

What happens at night- describing air circulation

Physics

1 answer:

mash [69]3 years ago

5 0

Answer:

The environment is warmed by the light throughout the day, such that the temperature increases. The weather is decreasing and the temperature decreases in the night as the sun falls. There was a misunderstanding. Thanks to the density, the atmosphere becomes densest on the earth. The air becomes colder and colder when you move up.

Explanation:

Answer is above

<em><u>Hope this helps.</u></em>

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What are the three main branches of science

ipn [44]

physical science, Earth science and life science

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3 years ago

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Light of wavelength 648.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 57.5 cm from the slit.

boyakko [2]

Answer:

$71.0 \mu m$

Explanation:

The formula for the single-slit diffraction is

$y=\frac{n\lambda D}{d}$

where

y is the distance of the n-minimum from the centre of the diffraction pattern

D is the distance of the screen from the slit

d is the width of the slit

$\lambda$ is the wavelength of the light

In this problem,

$\lambda=648.0 nm=6.48\cdot 10^{-7}m$

$D=57.5 cm=0.575 m$

$y=1.05 cm=0.0105 m$ , with n=2 (this is the distance of the 2nd-order minimum from the central maximum)

Solving the formula for d, we find:

$d=\frac{n\lambda D}{y}=\frac{2(6.48\cdot 10^{-7} m)(0.575 m)}{0.0105 m}=7.10\cdot 10^{-5} m= 71.0 \mu m$

6 0

3 years ago

In a double-slit interference experiment, the wavelength is λ = 432 nm, the slit separation is d = 0.100 mm, and the screen is d

andrew-mc [135]

In the double-slit interference experiment, the distance of the nth-maximum from the center of the screen is given by
$y= \frac{n \lambda D}{d}$
where
$\lambda$ is the wavelength
D is the distance between the screen and the slits
d is the distance between the slits

In our problem,
$\lambda=432 nm= 432 \cdot 10^{-9} m$
$D=42.0 cm=0.42 m$
$d=0.100 mm=0.1 \cdot 10^{-3} m$

By applying the previous formula, we can calculate the distance of the 4th maximum from the center of the screen:
$y_4 = \frac{(4)(432 \cdot 10^{-9} m)(0.42 m)}{(0.1 \cdot 10^{-3}m)}=7.25 \cdot 10^{-3} m$

Similarly, the distance of the 8th- maximum is
$y_8 = \frac{(8)(432 \cdot 10^{-9} m)(0.42 m)}{(0.1 \cdot 10^{-3}m)}=14.5 \cdot 10^{-3} m$

Therefore, the distance between the two maxima is
$\Delta y=y_8- y_4 = 14.5 \cdot 10^{-3} m- 7.25 \cdot 10^{-3} m =7.25 \cdot 10^{-3} m = 7.25 mm$

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4 years ago

The part of a circult that increases the electric potential of the electrons is the

Tanya [424]

Answer:

The part of a circuit that increases the electric potential of the electrons is the battery.

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3 years ago

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What happens when the forces are applied on an object in the same direction ?

kykrilka [37]

Answer:

if the object is already moving and a force is applied in the same direction, the object will speed up or accelerate.

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3 years ago