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Evgen [1.6K]
3 years ago
8

A car’s momentum is p when it is traveling with a velocity of v. If the velocity of that car doubles, what is the new momentum o

f the car?
Physics
2 answers:
abruzzese [7]3 years ago
7 0

Answer:

c. 2p

Explanation:

edge 2021

lubasha [3.4K]3 years ago
5 0

Answer:

∆p=(m2v)kg.m/s

Explanation:

∆p=mv where v=2v. hence ∆p=m2v

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Without knowing anything about their magnitudes or directions, the only thing you can always say about thier combination is that it's the "net force" on the object.
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What can parents do if they find a mistake in the student records?      A. They can’t do anything B. Make a correction themselve
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D. Ask the school to make the correction
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Read 2 more answers
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Tanya [424]

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Reset

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3 years ago
( Image is 6 C carbon with the numbers 12.011 under it ) According to the image, the atomic mass of carbon is 12.011. How is the
Oduvanchick [21]

Answer:

B. By adding the number of protons and the number of neutrons

Explanation:

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In order to ascertain atomic mass, we therefore add the number of protons and neutrons together. This is how we arrive at 12.011 as the value of the atomic mass of C and for other elements.

The atomic mass is also known as the mass number.

4 0
3 years ago
A glider with mass m = 0.230 kg sits on a frictionless horizontal air track, connected to a spring with force constant k = 4.50
loris [4]

Answer

given,

mass of glider = 0.23 Kg

spring constant = k = 4.50 N/m

spring stretched to 0.130 m

The springs potential energy =

 U = \dfrac{1}{2}kx^2

 U = \dfrac{1}{2}\times 4.5 \times 0.13^2

        U = 0.038 J

at x = 0,the only energy will be kinetic .

 \dfrac{1}{2}mv^2=0.038

 \dfrac{1}{2}\times 0.23 \times v^2=0.038

         v² = 0.3304

         v = 0.575 m/s

displacement of the glider

      using conservation of energy

 \dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2

 x =v\sqrt{\dfrac{m}{k}}

 x =3\times \sqrt{\dfrac{0.23}{4.5}}

        x = 0.678 m

8 0
3 years ago
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