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3 years ago

Explain electric circuits. Be sure to include the features, the roles, and the types. Help PLEASEEEE!!

1 answer:

5 0

If there was any way to do that, then your teacher wouldn't
need to keep you coming into class every day and doing
homework every night. She could just give you the 3 or 4
paragraphs and a few pictures that you're asking me for,
and bada-bing ! you'd know it !

The time it takes, and the amount of homework it takes, is
EXACTLY the time you spent hearing about it in class.

(Unless you're some kind of genius savant prodigy, which
you're not and I'm not.)

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Please help ASAP.

Elden [556K]

Answer:

1st question c part

2nd question c part

8 0

3 years ago

Why are objects that fall near earth’s surface rarely in free fall?

Sloan [31]

Answer:

Because of the presence of air resistance

Explanation:

When an object is in free fall, ideally there is only one force acting on it:

- The force of gravity, W = mg, that pushes the object downward (m= mass of the object, g = acceleration of gravity)

However, this is true only in absence of air (so, in a vacuum). When air is present, it exerts a frictional force on the object (called air resistance) with upward direction (opposite to the motion of free fall) and whose magnitude is proportional to the speed of the object.

Therefore, it turns out that as the object falls, its speed increases, and therefore the air resistance acting against it increases too; as a result, the at some point the air resistance becomes equal (in magnitude) to the force of gravity: when this happens, the net acceleration of the object becomes zero, and so the speed of the object does not increase anymore. This speed reached by the object is called terminal velocity.

3 0

3 years ago

The energy levels of one‑electron ions are given by the equation En=(−2.18×10−18 J)(Z^2/n^2) where Z is atomic number and n is t

Alexxandr [17]

Answer:

$\lambda=4.86*10^{-7}m$

Explanation:

Using the given equation, we calculate the energy associated with the excited state $n_i=8$ and $n_f=4$

$E_n=\frac{-2.18*10^-18J(Z^2)}{n^2}$

Helium has an atomic number (Z) equal to 2, for n=8:

$E_8=\frac{-2.18*10^{-18}J(2^2)}{8^2}\\E_8=-1.36*10{-19}J$

For n=4:

$E_4=\frac{-2.18*10^{-18}J(2^2)}{4^2}\\E_4=-5.45*10{-19}J$

When an electron jumps from an energy level with greater energy $E_i$ to one with lower energy $E_f$ the wavelength of the emitted photon is given by:

$\lambda=\frac{hc}{E_i-E_f}$

h is the Planck constant and c the speed of light in vaccum. So, we have:

$\lambda=\frac{hc}{E_8-E_4}\\\lambda=\frac{6.63*10^{-34}J \cdot s(3*10^8\frac{m}{s})}{-1.36*10{-19}J-(-5.45*10{-19}J)}\\\lambda=4.86*10^{-7}m$

5 0

3 years ago

Many types of decorative lights are connected in parallel. If a set of lights is connected to a 110 V source and the filament of

Oksi-84 [34.3K]

Answer:

i₀ = V / R_i

Explanation:

For this exercise we use Ohm's law

V = i R

i = V / R

the equivalent resistance for

$\frac{1}{R_{eq}}$ = ∑ $\frac{1}{R_i}$

if all the bulbs have the same resistance, there are N bulbs

$\frac{1}{ R_{eq}} = \frac{N}{R_i}$

R_{eq} = R_i / N

we substitute

i = N V / Ri

where i is the total current that passes through the parallel, the current in a branch is

i₀ = i / N

i₀ = V / R_i

3 0

3 years ago

Help....................

Nastasia [14]

<h3>Answer:- </h3><h3>16000 </h3><h3> Explanation:-</h3><h3 /><h3>force = 800N</h3><h3>area of 1 feet = 0.025</h3><h3>Area of 2 feet= 0.025+0.025 = 0.050m²</h3><h3>presure = force / area </h3><h3> = 800 N / 0.050</h3><h3> = 16000</h3>

3 0

3 years ago