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2 years ago

Explain electric circuits. Be sure to include the features, the roles, and the types. Help PLEASEEEE!!

1 answer:

5 0

If there was any way to do that, then your teacher wouldn't
need to keep you coming into class every day and doing
homework every night. She could just give you the 3 or 4
paragraphs and a few pictures that you're asking me for,
and bada-bing ! you'd know it !

The time it takes, and the amount of homework it takes, is
EXACTLY the time you spent hearing about it in class.

(Unless you're some kind of genius savant prodigy, which
you're not and I'm not.)

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If the velocity of a body changes from 13 m/s to 30 m/s while undergoing constant acceleration, what's the average velocity of t

Ronch [10]

Since the acceleration is constant, the average velocity is simply the average of the initial and final velocities of the body:

$v_{avg} = \frac{v_f+v_i}{2}=\frac{30 m/s+13 m/s}{2}=21.5 m/s$

We can proof that the distance covered by the body moving at constant average velocity $v_{avg}$ is equal to the distance covered by the body moving at constant acceleration a:

- body moving at constant velocity $v_{avg}$ : distance is given by

$S=v_{avg}t = \frac{v_f+v_i}{2}t$

- body moving at constant acceleration $a=\frac{v_f-v_i}{t}$ : distance is given by

$S=v_i t+ \frac{1}{2}at^2 = v_i t + \frac{1}{2}\frac{v_f-v_i}{t}t^2=(v_i+\frac{1}{2}(v_f-v_i))t=\frac{v_f+v_i}{2}t$

7 0

2 years ago

Read 2 more answers

What are the formulae of momentun and their time of use

Ivanshal [37]

Answer:

???????????????????????????

6 0

2 years ago

What is this question formula a=V²-U² /2S?

erik [133]

Answer:

sorry I don't really know about that question.

Explanation:

7 0

2 years ago

For horizontally-launched projectiles, which of the following describes acceleration in both directions with a = 0 and a = -9.8m

natulia [17]

Answer:

4 is the best option for it as there are some stuff in grade to ye

5 0

2 years ago

The patellar tendon attaches to the tibia at a 20 deg angle 3 cm from the axis of rotation at the knee. If the force generated i

gregori [183]

Answer:

the resulting angular acceleration is 15.65 rad/s²

Explanation:

Given the data in the question;

force generated in the patellar tendon F = 400 N

patellar tendon attaches to the tibia at a 20° angle 3 cm( 0.03 m ) from the axis of rotation at the knee.

so Torque produced by the knee will be;

T = F × d⊥

T = 400 N × 0.03 m × sin( 20° )

T = 400 N × 0.03 m × 0.342

T = 4.104 N.m

Now, we determine the moment of inertia of the knee

I = mk²

given that; the lower leg and foot have a combined mass of 4.2kg and a given radius of gyration of 25 cm ( 0.25 m )

we substitute

I = 4.2 kg × ( 0.25 m )²

I = 4.2 kg × 0.0626 m²

I = 0.2625 kg.m²

So from the relation of Moment of inertia, Torque and angular acceleration;

T = I∝

we make angular acceleration ∝, subject of the formula

∝ = T / I

we substitute

∝ = 4.104 / 0.2625

∝ = 15.65 rad/s²

Therefore, the resulting angular acceleration is 15.65 rad/s²

8 0

2 years ago