3 years ago

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Physics

1 answer:

Lady_Fox [76]3 years ago

5 0

Explanation:

Sorry i had to post it here. This is for the chemistry question on The top

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Match the following:

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A proton moves through a magnetic field at 26.7 % 26.7% of the speed of light. At a location where the field has a magnitude of

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$8.64283\times 10^{-14}\ N$

Explanation:

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v = Velocity of proton = $0.267\times c$

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$\theta$ = Angle = $101^{\circ}$

Magnetic force is given by

$F=qvBsin\theta\\\Rightarrow F=1.6\times 10^{-19}\times (0.267\times 3\times 10^8)\times 0.00687\times sin101\\\Rightarrow F=8.64283\times 10^{-14}\ N$

The magnetic force acting on the proton is $8.64283\times 10^{-14}\ N$

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HELP ASAP! PLEASEEEE ​

HELP ASAP! PLEASEEEE