Answer:
The speed of the chair just before impact is 22.54 m/s
Explanation:
From the question,
The chair was initially at rest, that is, the initial velocity of the chair is 0 m/s.
Since the chair was thrown from a balcony, the chair will fall freely due to gravity.
To determine the speed of the chair just before impact, we will determine the final velocity of the chair.
From one of the equations of linear motion for objects falling freely due to gravity,
v = u + gt
Where v is the final velocity
u is the initial velocity
g is the acceleration due to gravity (Take g = 9.8 m/s²)
and t is time
From the question,
u = 0 m/s
t = 2.3 secs
Then, v = u + gt becomes
v = 0 + (9.8)(2.3)
v = 9.8 × 2.3
v = 22.54 m/s
Hence, the speed of the chair just before impact is 22.54 m/s.
Answer:
0.45 m/s in the negative x-direction
Explanation:
From the law of conservation of momentum, the sum of initial momentum equals the sum of final momentum
Momentum, p=mv where m is the mass and v is the velocity
where is the common velocity, and are velocities of magnet moving in positive x-direction and magnet moving in negative x-direction respectively, and are masses of magnet moving in positive x-direction and magnet moving in negative x-direction respectively.
Substituting 125 g for and 85 g for , 7.33 m/s , -11.9 m/s for then
Therefore, the velocity of single unit is 0.45 m/s in the negative x-direction
Answer:
Part a)
charge on each sphere is -1.95 micro coulomb
Part b)
For first sphere
excess charge
For second sphere
excess charge
For third sphere
absent charge
For third sphere
absent charge
Explanation:
Part a)
Since all the spheres are of identical size so the total charge of the sphere will divide equally on them
So we have
So charge on each sphere is -1.95 micro coulomb
Part b)
For first sphere
initial charge = 2.2 micro coulomb
final charge = -1.95 micro coulomb
excess charge = -1.95 - 2.2 = -4.15 micro coulomb
Q = Ne
For second sphere
initial charge = 4.2 micro coulomb
final charge = -1.95 micro coulomb
excess charge = -1.95 - 4.2 = -6.15 micro coulomb
Q = Ne
For third sphere
initial charge = -7.4 micro coulomb
final charge = -1.95 micro coulomb
absent charge = -1.95 + 7.4 = 5.45 micro coulomb
Q = Ne
For third sphere
initial charge = -6.8 micro coulomb
final charge = -1.95 micro coulomb
absent charge = -1.95 + 6.8 = 4.85 micro coulomb
Q = Ne
Answer
given,
mass of disk = 2 Kg
radius = 0.1 m
time = 10 sec
a) 800 rpm to rad/s
=
=
b) 740 rpm to rad/s
=
=
c) Angular acceleration
d) moment of inertia of disc
I = 0.01 Kg.m²
e) τ = I α
τ = 0.01 x 0.629
τ = 6.29 x 10⁻³ N.m
f) impulse = Force x time
J = 0.629 Ns
g) Work done
W = Δ KE
W = 5.07 J