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2 years ago

Please help & actually answer thank you :)

Physics

1 answer:

Katarina [22]2 years ago

4 0

Answer:

0.5x35=17.5

Explanation:

You throw 0.5 kg the ball leaves your hand with

A speed of 35

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Given that a lever has a mechanical advantage of 6.0 and is 100% efficient, if the resistance is to be lifted 2.0 inches, then h

Shalnov [3]

The mechanical advantage of a machine is the ratio of the force produced by the machine to the force applied to it. Therefore, we may calculate the applied force using:
Mechanical advantage = force by machine / force applied
6 = 2 / force applied
Force applied = 1/3

Thus, the distance that the effort must move will be 1/3 inch

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3 years ago

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While looking at bacteria under a microscope you decide to take a break when u return the amount of bacteria has doubled in size

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3 years ago

Two people carry a heavy object by placing it on a board that is 2.2 meters long. One person lifts with a force of 750 N at one

stiks02 [169]

Answer:

This means that the center of mass is locates 0.72m from the 750N force

Explanation:

Since the board is 2.2m long, that will be the length of the board.

Let the center of mass of the body be hinged at the center using a knife edge as shown in the diagram attached.

Let x be the distance from the 750N force to the knife edge and the distance from the 360N force to the knife edge be 2.2-x

Using the principle of moment which states that the sum of clockwise moment is equal to the sum of anti clockwise moment.

Moment = force × perpendicular distance

For ACW moment;

Moment = 750×x = 750x

For the CW moment;

Moment = 360 × (2.2-x)

Moment = 792-360x

Equating ACW moment to the clockwise moment we have;

750x = 792-360x

750x+360x = 792

1110x = 792

x = 792/1110

x = 0.72m

This means that the center of mass is locates 0.72m from the 750N force

3 0

3 years ago

How much force is required to accelerate a 4 kg bowling ball from 0 m/s to 2 m/s in 1 second? what amount of energy does the bow

Vladimir [108]

Well, F = ma

and a= change in vel / change in time
= (2-0 ) / 1 = 2 m^2/s

so, F= 4* 2 = 8 N

and W = F.S = 8 * 2 = 16 J

hope it helped

5 0

3 years ago

At what frequency should a 200-turn, flat coil of cross sectional area of 300 cm2 be rotated in a uniform 30-mT magnetic field t

stellarik [79]

Answer:

The frequency of the coil is 7.07 Hz

Explanation:

Given;

number of turn of the coil, N = 200 turn

area of the coil, A = 300 cm² = 0.03 m²

magnitude of magnetic field, B = 30 mT = 0.03 T

maximum value of induced emf, E = 8 V

The maximum induced emf in the coil is given by;

E = NBAω

E = NBA(2πf)

$f = \frac{E_{max}}{2\pi*NBA}$

where;

f is the frequency of the coil

$f = \frac{E_{max}}{2\pi*NBA}\\\\f = \frac{8}{2\pi(200)(0.03)(0.03)} \\\\f = 7.07 \ Hz$

Therefore, the frequency of the coil is 7.07 Hz

5 0

3 years ago