Answer:
3.5434 eV
Explanation:
For a particle with kinetic energy E and mass m , the wavelength associated is given by the following relation,
E = 
Putting the values we get
E = 
=1.063 x 10⁻²¹ J
= .0066 eV.
Energy of¹light in terms of eV
= 1244 / 350 = 3.55 eV.
Work function = 3.55 - 0.0066 = 3.5434 eV.
Answer:
The energy of the photon from the higher-wattage bulb is equal to the energy of the photon from the lower-wattage bulb.
Explanation:
Answer:
(a)-0.701m
(b)-0.674m/s
Explanation:
Given a = -0.24,m/s² Xo = 0.170m, u = 0.190m/s
X = Xo + ut +1/2at²
X = 0.170 + 0.190×3.6 + 1/2×(-0.24) 3.6² = -0.701m
(b) its velocity at the end of this time interval is v
v = u + at
= 0.190 + (-0.24)× 3.6 = -0.674m/s
