A fuel injection system that does not use a sensor to measure the amount (or mass) of air entering the engine is usually called speed density type of system.
<h3>What is speed density fuel injection system?</h3>
Speed density fuel injection system is a fuel delivery method.
This system relies on a combination of sensor and an intake air temperature sensor to measure the amount (or mass) of air entering the engine.
Thus, a fuel injection system that does not use a sensor to measure the amount (or mass) of air entering the engine is usually called speed density type of system.
Learn more about speed density here: brainly.com/question/26024294
I say it is false that is the correct answer
Actually, they're not. There's a group of stars and constellations arranged
around the pole of the sky that's visible at any time of any dark, clear night,
all year around. And any star or constellation in the rest of the sky is visible
for roughly 11 out of every 12 months ... at SOME time of the night.
Constellations appear to change drastically from one season to the next,
and even from one month to the next, only if you do your stargazing around
the same time every night.
Why does the night sky change at various times of the year ? Here's how to
think about it:
The Earth spins once a day. You spin along with the Earth, and your clock is
built to follow the sun . "Noon" is the time when the sun is directly over your
head, and "Midnight" is the time when the sun is directly beneath your feet.
Let's say that you go out and look at the stars tonight at midnight, when you're
facing directly away from the sun.
In 6 months from now, when you and the Earth are halfway around on the other
side of the sun, where are those same stars ? Now they're straight in the
direction of the sun. So they're directly overhead at Noon, not at Midnight.
THAT's why stars and constellations appear to be in a different part of the sky,
at the same time of night on different dates.
Answer:
Maximum height of the ball, h(t) = 27.56 m
Explanation:
It is given that, a ball is shot from the ground straight up into the air with initial velocity of 42 ft/sec.
The height of the ball as a function of time t is given by :
h₀ is initial height, h₀ = 0
So, 
.........(1)
For maximum/minimum height, 
...(2)
t = 1.31 s
Differentiating equation (2) wrt t
h''(t) = -32 < 0
So, at t = 1.31 seconds we will get the maximum height.
Put the value of t in equation (1)
h(t) = 27.56 m
Hence, this is the required solution.
