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Dovator [93]
3 years ago
10

When you push on an object such as a wrench, a steel pry bar, or even the outer edge of a door, you produce a torque equal to th

e force applied times the lever arm. at what angle to the lever arm should a force be applied to produce maximum torque and why?
Physics
1 answer:
Korvikt [17]3 years ago
5 0
<span>Since youc oncetrate all your force directly towards the moment arm it means that you push  it at an angle  of your force is directed to the left or the right and I bet that it must be 90</span> degrees to the bar. Obviuosly, if you are about to push it you will do it  straight up but not in a zig zag way. In other words, it should be perpendicular to the arm because the<span> torque can be produced only if force is applied at a constant index (90).
Hope that helps! Regards.</span>
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Answer:

B. Solids are highly compressible

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3 years ago
A 1-kg plastic block is neutrally buoyant when submerged in water with a density of 1 g/cm3. If the same block is placed, such t
goldenfox [79]

Answer:

-2 m/s

Explanation:

The computation of the acceleration of the block is as follows:

The volume of the block is

V = 1kg ÷ 1,000 kg/m^3 = 1 ÷ 1,000 m^3

Now at the time of submerging in the oil

Net force is

m_g - F_B = m \times (-a)\\\\m_g - v\times S_{oil} \times g = -ma\\\\a = (\frac{v}{m} \times S_{oil}  - 1) g\\\\= (\frac{1}{1000} \times 0.8 \times 1000 -1 ) \times 10\\\\

= -2 m/s

8 0
3 years ago
If a galaxy is located 200 million light years from Earth, what can you conclude about
timofeeve [1]

Answer:

D

Explanation:

It's quite simple actually, you see, what light years basically means is how many years light takes to travel from point a to point b. So here it says that a galaxy is 200 million light years away. So since that light is 200 million years away, it would take 200 million years until that light reaches us.

5 0
3 years ago
A hollow cylinder is given a velocity of 5.3 m/s and rolls up an incline to a height of 2.87 m. If a hollow sphere of the same m
Valentin [98]

Answer:

E = 1/2 M V^2 + 1/2 I ω^2 = 1/2 M V^2 + 1/2 I V^2 / R^2

E = 1/2 M V^2 (1 + I / (M R^2))

For a cylinder I = M R^2

For a sphere I = 2/3 M R^2

E(cylinder) = 1 + 1 = 2       omitting the 1/2 M V^2

E(sphere) = 1 + 2/3 = 1.67

E(cylinder) / E(sphere) = 2 / 1.67 = 1.2

The cylinder initially has 1.20 the energy of the sphere

The PE attained is proportional to the initial KE

H(sphere) = 2.87 / 1/2 = 2.40 m    since it has less initial KE

5 0
2 years ago
Two masses are separated by a distance r. If this distance is doubled, is the force of interaction between the two masses double
baherus [9]

Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

This is mathematically represented as

<u>F= (G X m1 x m2) /r∧2</u>

where F is the force acting between the charged particles

r is the distance between the two charges measured in m

G is the gravitational constant which has a value of <em>6.674×10^-11 Nm^2 kg^-2</em>

m1 and m2 are the masses of the objects measured in Kg

Now if the distance between the is doubled then r becomes 2r. Substituting this in the above formula we get the new Force as

Force (new) = (G X m1 x m2) /(2r)∧2


Thus dividing Force(new)/Force we get

Force(new)/Force = 1/4.

Thus the gravitational force becomes 1/4th of the original value if the distance between the two masses are doubled.




7 0
3 years ago
Read 2 more answers
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