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2 years ago

A school bus moves at speed of 35 mi/hr for 20 miles. How long will it take the bus to get to school?

Physics

2 answers:

Irina18 [472]2 years ago

7 0

The time required for the bus to get to school (in hours) is

(the distance from here to school) divided by (35 mi/hr) .

In order to find the actual number, we would need to know the distance from here to school.

mafiozo [28]2 years ago

4 0

Answer:

Time, t = 0.57 hours

Explanation:

It is given that,

Speed of the school bus, v = 35 mi/hr

Distance covered by the bus, d = 20 miles

We need to find the time taken by the bus to get to school. Time taken by the bus is given by :

$t=\dfrac{d}{v}$

$t=\dfrac{20\ mi}{35\ mi/hr}$

t = 0.57 hours

So, the time taken by the bus to reach school is 0.57 hours. Hence, this is the required solution.

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2 years ago

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3 years ago

Lighting a match changes chemical energy into heat and light. The total amount of energy _____.

Mariulka [41]

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The answer is remains the same.

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2 years ago

Read 2 more answers

Charge A and charge B are 3.00 m apart, and charge A is +1.44 C and charge B is +3.10 C. Charge C is located between them at a c

Sidana [21]

Answer:

the distance from charge A to C is r₁₃= 1.216 m

Explanation:

following Coulomb's law , the force exerted by 2 point charges between themselves is:

F= k*q₁*q₂/r₁₂² , where q is charge , r is distance and 1 and 2 represents the charge A and charge B respectively , k=constant

since C ( denoted as 3) is at equilibrium

F₁₃=F₂₃

k*q₁*q₃/r₁₃²=k*q₂*q₃/r₂₃²

q₁/r₁₃²=q₂/r₂₃²

r₁₃²/q₁=r₂₃²/q₂

r₂₃=r₁₃*√(q₂/q₁)

since C is at rest and is co linear with A and B ( otherwise it would receive a net force in either vertical or horizontal direction) , we have

r₁₃+r₂₃=d=r₁₂

r₁₃+r₁₃*√(q₂/q₁)=d

r₁₃*(1+√(q₂/q₁))=d

r₁₃=d/(1+√(q₂/q₁))

replacing values

r₁₃=d/(1+√(q₂/q₁)) = 3.00 m/(1+√(3.10 C/1.44 C)) = 1.216 m

thus the distance from charge A to C is r₁₃= 1.216 m

7 0

2 years ago

I wish to use a step up transformer to turn an initial RMS AC voltage of 100 V into a final RMS AC voltage of 200 V. What is the

zhuklara [117]

Answer:

1:2

Explanation:

It is given that,

Initial RMS AC voltage is 100 V and final RMS AC voltage is 200 V.

We need to find the ratio of the number of turns in the primary to the secondary for step up transformer.

For a transformer, $\dfrac{V_1}{V_2}=\dfrac{N_1}{N_2}$

So,

$\dfrac{N_1}{N_2}=\dfrac{100}{200}\\\\\dfrac{N_1}{N_2}=\dfrac{1}{2}$

So, the ratio of the number of turns in the primary to the secondary is 1:2.

4 0

2 years ago