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3 years ago

Alfred wegener was the one who made contiental drift theory ?

1 answer:

4 0

Yep. he discovered that coastline from south america and africa fit together like a puzzle, which later became a part of the continential drift theory

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What is the study of kinematics based upon ?<br><br>thankyou ~

NikAS [45]

Kinematics is the study of the motion of a system of bodies without directly considering the forces or potential fields affecting the motion. In other words, kinematics examines how momentum and energy are shared among interacting bodies.

8 0

2 years ago

As a skydiver accelerates downward, what force increases? A. Gravity B. Thrust C. Air resistance D. Centripetal

dybincka [34]

Answer:

(A) Gravity is you're answer.

Explanation:

When an object or human is falling at an increased rate, The force of gravity is taking place.

7 0

3 years ago

How many air molecules are in a 13.0×12.0×10.0 ft room (28.2 L=1 ft3)? Assume atmospheric pressure of 1.00 atm, a room temperatu

aksik [14]

Answer:

1963.93 Moles

Explanation:

-We know the standard conversion ratio for the volume of a mole is $1 Mole=22.4L$

Given volume of rooms as $13.0ft\times12.0ft\times10ft=1560 ft^3$

Convert the volume into liters: $1560\times28.2l=43992l$

#From our conversion ratio above, we get the volume of air molecules in moles as:

$V_m=\frac{43992L}{22.4L}\times 1\ mole\\\\=1963.93\ Moles$

Hence, the volume of air molecules is 1963.93 Moles

4 0

3 years ago

An astronaut on the moon drops a feather from rest (v = 0). The acceleration due to gravity is 1.67 m/s 2 . If the feather beg

olga_2 [115]

Given :

Initial velocity , u = 0 m/s .

Acceleration due to gravity on moon , $g_m=1.67\ m/s^2$ .

Height , h = 2 m .

To Find :

Final position after falling for 1.5 seconds .

Solution :

We know , by equation of motion :

$s=ut+\dfrac{at^2}{2}$

Here , $a = g_m$ .

So , equation will transform by :

$s=ut+\dfrac{g_mt^2}{2}\\\\s=0+\dfrac{1.67\times 1.5^2}{2}\ m\\\\s=1.88\ m$

Therefore , the height form moon's surface is 1.88 m .

Hence , this is the required solution .

6 0

3 years ago

7) A ball is thrown upward at an initial velocity of 8.2 m/s, from a height of 1.8 meters above the ground. The height of the ba

Dima020 [189]

$\\ \tt \longmapsto \: h = - 4.8 {t}^{2} + 8.2t + 1.8 \\ \\ \tt \longmapsto \: h = - 4.8(1.7) {}^{2} + 8.2 \times 1.7 + 1.8 \\ \\ \tt \longmapsto \: - 4.8 \times 2.89 + 1.39 + 1.8 \\ \\ \tt \longmapsto \: 13.8 + 1.39 + 1.8 \\ \\ \tt \longmapsto \: 17.06$

6 0

3 years ago