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2 years ago

Alfred wegener was the one who made contiental drift theory ?

1 answer:

4 0

Yep. he discovered that coastline from south america and africa fit together like a puzzle, which later became a part of the continential drift theory

You might be interested in

A ________ is a device that converts digital signals from a computer into analog signals so that telephone lines may be used as

kipiarov [429]

Answer:

analog-to-digital

Explanation:

An analog-to-digital converter, or ADC as it is more commonly called, is a device that converts analog signals into digital signals.

6 0

2 years ago

A small ball with mass 2.50 kg is mounted on one end of a rod 0.750 m long and of negligible mass. The system rotates in a horiz

alina1380 [7]

Answer:

1.40625 kg-m^2

Explanation:

Supposing we have to calculate rotational moment of inertia

Given:

Mass of the ball m= 2.50 kg

Length of the rod, L= 0.78 m

The system rotates in a horizontal circle about the other end of the rod

The constant angular velocity of the system, ω= 5010 rev/min

The rotational inertia of system is equal to rotational inertia of the the ball about other end of the rod because the rod is mass-less

$I_{sys}= mL^2= 2.50\times 0.75^2$

=1.40625 kg-m^2

m= mass of the ball and L= length of the ball

3 0

2 years ago

Convert 60 miles/hour to m/s (1.6km = 1mile; 1000m = 1km)

Sedaia [141]

60 miles / hr

= 60 * 1.6 * 1000 m / 60 * 60 s

= 96000 m / 3600 s

= 26.67 m / s

8 0

2 years ago

How much energy is stored in a spring with a spring constant of 390 N/m if the spring is compressed a distance of 0.45 m from it

masya89 [10]

F=-ks
F=-(390)(.45)
F=-175.5 N

Work=force x displacement
Work= 175.5(0.45)
Work= 78.98 J

Work = ∆E =78.98 J

Answer=79J (first option)

4 0

2 years ago

An elevator cab and its load have a combined mass of 1200 kg. Find the tension in the supporting cable when the cab, originally

Nadya [2.5K]

Answer:

10044 N

Explanation:

The acceleration of the cab is calculated using the equation of motion:

$v^2 = u^2+2as$

v is the final velocity = 0 m/s in this question, since it is brought to rest

u is the initial velocity = 10 m/s

a is the acceleration

s is the distance = 35 m

$a = \dfrac{v^2-u^2}{2s} = \dfrac{(0 \text{ m/s})^2-(10 \text{ m/s})^2}{2\times (35\text{ m})} = -1.43\text{ m/s}^2$

Since it accelerates downwards, its resultant acceleration is

$a_R = g + a$

g is the acceleration of gravity.

$a_R = (9.8-1.43)\text{ m/s}^2 = 8.37\text{ m/s}^2$

The tension in the cable is

$T = ma_R = (1200\text{ kg})(8.37\text{ m/s}^2) = 10044 \text{ N}$

3 0

2 years ago