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Sauron [17]
3 years ago
13

Uring lunch hour at a local restaurant, 90% of the customers order a meat entrée and 10% order a vegetarian entrée. Of the custo

mers who order a meat entrée, 80% order a drink. Of the customers who order a vegetarian entrée, 40% order a drink. What is the percent of customers who order a drink with their entrée?
Mathematics
1 answer:
Furkat [3]3 years ago
3 0

Answer:

Total percent of customers who order a drink with their entrée = 76%

Step-by-step explanation:

Let

Total customers = 100%

customers who order a meat entrée = 90%

customers who order a vegetarian entrée = 10%

Of the customers who order a meat entrée, 80% order a drink

% of customers who order a meat entrée and drink = 80% of 90%

= (80/100 * 90/100) * 100

= (0.8 * 0.9) * 100

= 0.72 * 100

= 72%

% of customers who order a meat entrée and drink = 72%

Of the customers who order a vegetarian entrée, 40% order a drink.

% of customers who order a vegetarian entrée and drink = 40% of 10%

= (40/100 * 10/100) * 100

= (0.4 * 0.1) * 100

= 0.04 * 100

= 4%

% of customers who order a vegetarian entrée and drink = 4%

What is the percent of customers who order a drink with their entrée?

Total percent of customers who order a drink with their entrée = % of customers who order a meat entrée and drink + % of customers who order a vegetarian entrée and drink

= 72% + 4%

= 76%

Total percent of customers who order a drink with their entrée = 76%

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