A roller coaster car has a mass of 400kg and a speed of 15m/s What will be the P.E of this roller coaster car at its highest poi
1 answer:
Answer:
3000J
Explanation:
Given parameters:
mass = 400kg
speed = 15m/s
Unknown:
P.E at the highest point of the roller coaster = ?
Solution:
Due to the law of conservation of energy, the potential energy at the highest point can be solved using the formula of the kinetic energy
Potential energy = mv²
m is the mass
v is the velocity
Potential energy = x 400 x 15 = 3000J
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Answer:
a
The radial acceleration is
b
The horizontal Tension is
The vertical Tension is
Explanation:
The diagram illustrating this is shown on the first uploaded
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The length of the string is
The mass of the bob is
The angle made by the string is
The centripetal force acting on the bob is mathematically represented as
Now From the diagram we see that this force is equivalent to
where T is the tension on the rope and v is the linear velocity
So
Now the downward normal force acting on the bob is mathematically represented as
So
=>
=>
The centripetal acceleration which the same as the radial acceleration of the bob is mathematically represented as
=>
substituting values
The horizontal component is mathematically represented as
substituting value
The vertical component of tension is
substituting value
The vector representation of the T in term is of the tension on the horizontal and the tension on the vertical is
substituting value
Answer:
10 kg
Explanation:
Assuming a frictionless surface, then force F=ma where F is the applied force, m is the mass and a is acceleration. Making m the subject of the formula then
Substituting 100 N for the applied force F and 10 m/s^2 for acceleration a then the value of m will be
Therefore, in terms of kilograms, the bookshelf weighs 10 Kg