Newton's 2nd law of motion says
Net force = (mass) x (acceleration)
Plug in the things you know, and you have
80 N = (20 kg) x (acceleration)
Divide each side by (20 kg) :
80N / 20kg = acceleration
acceleration = 4 m/s²
The coefficients are 8 17 1 8
remember that we have to have the same amount of atoms on each side of the equation.
start with C there is 1 on the left and 8 on the right so 8 has to be on the CO. now there is an 8 now on the water there is 1 originally and now we need 8. from water there is now a total of 16 hydrogen plus the 18 from octane for a total of 34. the left has an H2. 34/2 = 17. that is where the 17 comes from
Answer:
It must be 4 times high.
Explanation:
- Assuming that the car can be treated as a point mass, and that the ramp is frictionless, the total mechanical energy must be conserved.
- This means, that at any time, the following must be true:
- ΔK (change in kinetic energy) = ΔU (change in gravitational potential energy)
⇒ 
- Let's call v₁, to the final speed of the car, and h₁ to the height of the ramp.
So, at the bottom of the ramp, all the gravitational potential energy
must be equal to the kinetic energy of the car (Defining the bottom of
the ramp as our zero reference for the gravitational potential energy):
(1)
- Now, let's do v₂ = 2* v₁
- Replacing in (1) we get:
(2)
- Dividing (2) by (1), and rearranging terms, we get:
- h₂ = 4* h₁
The total kinetic and potential energies