FE is iron CO is cobalt CU is copper K is potassium NI is nickle MN is magnemese
Answer: both hoops have the same kinetic energy at the bottom of the incline.
Explanation:
If we assume no work done by non conservative forces (like friction) , the total mechanical energy must be conserved.
K1 + U1 = K2 + U2
If both hoops start from rest, and we choose the bottom of the incline to be the the zero reference level for gravitational potential energy, then
K1 = 0 and U2 = 0
⇒ ΔK = ΔU = m g. h
If both inclines have the same height, and both hoops have the same mass m, the change in kinetic energy, must be the same for both hoops.
Answer: 
Explanation:
According to the conservation of linear momentum principle, the initial momentum
(before the collision) must be equal to the final momentum
(after the collision):
(1)
In addition, the initial momentum is:
(2)
Where:
is the mass of the comet
is the mass of the asteroid
is the velocity of the comet, which is positive
is the velocity of the asteroid, since it is at rest
And the final momentum is:
(3)
Where:
is the final velocity
Then :
(4)
Isolating
:
(5)

Finally:
This is the final velocity, which is also in the positive direction.
Answer:
mass multiplied by velocity (4 words but uh
Answer: <u>elastically</u> deformed or <u>non-permanently</u> deformed
Explanation:
According to classical mechanics, there are two types of deformations:
-Plastic deformation (also called irreversible or permanent deformation), in which the material does not return to its original form after removing the applied force, therefore it is said that the material was permanently deformed.
This is because the material undergoes irreversible thermodynamic changes while it is subjected to the applied forces.
-Elastic deformation (also called reversible or non-permanent deformation), in which the material returns to its original shape after removing the applied force that caused the deformation.
In this case t<u>he material also undergoes thermodynamic changes, but these are reversible, causing an increase in its internal energy by transforming it into elastic potential energy.</u>
<u />
Therefore, the situation described in the question is related to elastic deformation.