A factory worker pushes a 32.0 kg crate a distance of 7.0 m along a level floor at constant velocity by pushing horizontally on
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Answer:
3.49 seconds
3.75 seconds
-43200 ft/s²
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
Time the parachutist falls without friction is 3.19 seconds
Speed of the parachutist when he opens the parachute 31.32 m/s. Now, this will be considered as the initial velocity
So, time the parachutist stayed in the air was 3.19+0.3 = 3.49 seconds
Now the initial velocity of the last half height will be the final velocity of the first half height.
Since the height are equal
Time taken to fall the first half is 2.65 seconds
Total time taken to fall is 2.65+1.1 = 3.75 seconds.
When an object is thrown with a velocity upwards then the velocity of the object at the point to where it was thrown becomes equal to the initial velocity.
Magnitude of acceleration is -43200 ft/s²