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ololo11 [35]
3 years ago
8

If 5.00 g of Gas A and 5.00 g of Gas B are mixed in the same container, and the partial pressure of Gas B is determined to be tw

ice that of Gas A, what do we know about the gases? A) Gas A has half the molar mass of Gas B. B) Gas A has twice the molar mass of Gas B. C) Gas A has a higher temperature than Gas B. D) Gas A takes up twice the volume in the vessel than Gas B.
Chemistry
1 answer:
natita [175]3 years ago
8 0

Answer:

B) Gas A has twice the molar mass of Gas B.

Explanation:

Partial pressure of a gas is defined as the moles of the gas/ Total moles of the mixture times total pressure. The equation is:

Partial pressure A = Moles A / total moles * Total pressure

From the definition, we can say that the moles of the gas A are twice the moles of B:

2 Moles A = Moles B

As the mass of both gases is the same but the moles of B are twice the moles of A:

The molar mass of A is twice the molar mass of B

Right answer is:

<h3>B) Gas A has twice the molar mass of Gas B.</h3>
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A 232-lb fullback runs the 40-yd dash at a speed of 19.8 ± 0.1 mi/h.
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(a)  7.11 x 10⁻³⁷ m

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Explanation:

(a)  The de Broglie wavelength is given by the expression:

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where h is plancks constant, p is momentum which is equal to mass times velocity.

We have all the data required to calculate the wavelength, but first we will have to convert the velocity to m/s, and the mass to kilograms to work in metric system.

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m = 232 lb x ( 0.454 kg/ lb ) = 105.33 kg

λ = h/ mv = 6.626 x 10⁻³⁴ J·s / ( 105.33 kg x 8.85 m/s ) = 7.11 x 10⁻³⁷ m

(b) For this part we have to use the uncertainty principle associated with wave-matter:

ΔpΔx > = h/4π

mΔvΔx > = h/4π

Δx = h/ (4π m Δv )

Again to utilize this equation we will have to convert the uncertainty in velocity to m/s for unit consistency.

Δv = 0.1 mi/h x ( 1609.34 m/mi ) x ( 1 h/ 3600 s )  

     = 0.045 m/s

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     = 1.11 x 10⁻³⁵ m

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