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photoshop1234 [79]
3 years ago
5

When a drawing of a circle made in the center of a piece of paper with a black marker gets wet, the marker bleeds, and as the wa

ter moves through the paper the ink separates into several colors.
What method of separation does this describe?
evaporation
distillation
filtration
chromatography
Chemistry
2 answers:
suter [353]3 years ago
8 0

Answer:

D) Chromatography

Explanation:

WARRIOR [948]3 years ago
4 0

Answer: It is D. chromatography.

Step-by-step explanation:

when water or dye passes through a medium and changes color then that means it must be chromatography.

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What are the three states or matter? Whoever answers first, gets a follow bck
Elza [17]
Solid liquid and gas is the answer
8 0
3 years ago
Read 2 more answers
A balloon inflated in a room at 25oC has a volume of 3.00 L. If the balloon is heated at a constant pressure, at what temperatur
Alexeev081 [22]

Answer:

596K

Explanation:

Using Charles law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

V1 = 3.00 L

V2 = double of V1 = 2 × 3.00 = 6.00 L

T1 = 25°C = 25 + 273 = 298K

T2 = ?

Using V1/T1 = V2/T2

3/298 = 6/T2

Cross multiply

298 × 6 = 3 × T2

1788 = 3T2

T2 = 1788 ÷ 3

T2 = 596K

8 0
2 years ago
Consider just the first sentence of this multistep word problem. Sentence 1: The sum of the ages of a brother and sister is 26.
kiruha [24]

Answer:

a. b + s = 26

b. b = 26 — s

Explanation:

5 0
3 years ago
How many electrons are unpaired in the orbitals of carbon?
igor_vitrenko [27]

Answer:

2 unpaired electrons

Explanation:

Carbon's bonding state electron configuration is 1s2 2s1 2s1 2p1 2p1. So, there are 4 unpaired electrons in the orbitals of carbon in bonding state.

hope this helps

3 0
2 years ago
The following steps are unbalanced half-reactions involved in the nitrogen cycle. Balance each half-reaction to show the number
Vadim26 [7]

This is an oxidation reaction. The balanced equation is as follows:

      6H₂O  + N₂ → 2NO₃⁻+ 12H⁺  + 6e⁻

Rules to balance redox reaction in acidic medium

  1. Write the given equation in ionic form
  2. Identify elements undergoing oxidation ( charge increase, O.N inc) and reduction (charge dec, O.N dec)
  3. Break the equation into two halfs
  4. Balance the half equations

A. Balance all other atoms except Oxygen and hydrogen

B. Balance oxygen by adding H2O to the side deficient in oxygen

C. Balance hydrogen by adding H+ ions

D. Balance charge by adding electrons

5. Add the two half such that electrons gets cancelled

Oxidation number of N in N2 is 0 while in NO₃⁻, it is +5. Thus there is an increase in oxidation number, thus oxidation is taking place.

              N₂(g) → NO₃⁻(aq)

  • balance N.

           N₂ → 2NO₃⁻

  • balance O by adding H2O

          6H₂O  + N₂ → 2NO₃⁻

  • Now balance Hydrogen

            6H₂O  + N₂ → 2NO₃⁻+ 12H⁺

  • balance charge. 0 charge on left, -6 and + 12 on right. add 6e⁻ on right to balance.

             6H₂O  + N₂ → 2NO₃⁻+ 12H⁺  + 6e⁻

Thus we can conclude that since there is increase in oxidation number, oxidation is taking place.

learn more about balancing redox reactions at brainly.com/question/10203480

#SPJ4

3 0
1 year ago
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