Answer:
F = 1,875 N
Explanation:
force=
∆H = m∆V
where ∆H ----> change in momentum.
( final momentum - initial momentum )
and ∆V ----> change in velocity
( final velocity - initial velocity )
and m ----> is mass
then f =
= 1,875 N
what can you say about the motion of an object if its speed time graph is a straight line parallel to the time axis ? Also draw
a diagram and plese do it on paper , in above picture Q 2 is an example you can do Q3 according to Q2 
1 answer:
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Answer:
we use the formula,
h= 107 m
Answer:
Approximately . (Assuming that the drag on this ball is negligible, and that
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Explanation:
Assume that the drag (air friction) on this ball is negligible. Motion of this ball during the descent:
- Horizontal: no acceleration, velocity is constant (at
is constant throughout the descent.)
- Vertical: constant downward acceleration at
, starting at
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The horizontal velocity of this ball is constant during the descent. The horizontal distance that the ball has travelled during the descent is also given: . Combine these two quantities to find the duration of this descent:
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In other words, the ball in this question start at a vertical velocity of , accelerated downwards at
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Apply the SUVAT equation to find the vertical displacement of this ball.
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In other words, the ball is below where it was before the descent (hence the negative sign in front of the number.) The height of this cliff would be
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