I believe that the answer to the question asked above is the following
sound intensity = sound power / (4 pi R2<span>)
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so if you decrease the intensity by a factor of 2 the sound wave will also decrease by a factor of 2.
Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.
Answer:
The gauge pressure in Pascals inside a honey droplet is 416 Pa
Explanation:
Given;
diameter of the honey droplet, D = 0.1 cm
radius of the honey droplet, R = 0.05 cm = 0.0005 m
surface tension of honey, γ = 0.052 N/m
Apply Laplace's law for a spherical membrane with two surfaces
Gauge pressure = P₁ - P₀ = 2 (2γ / r)
Where;
P₀ is the atmospheric pressure
Gauge pressure = 4γ / r
Gauge pressure = 4 (0.052) / (0.0005)
Gauge pressure = 416 Pa
Therefore, the gauge pressure in Pascals inside a honey droplet is 416 Pa
Radial acceleration is given by
where
then
Now
Using the relation
Putting into rpm
Answer
A thin atmosphere does not supply much oxygen, and the heat from the sun would evaporate it, because mercury is close to the sun.
