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Kay [80]
4 years ago
9

What is the momentum of A 200 kg shark swimming at 15 m/s

Physics
1 answer:
Jlenok [28]4 years ago
7 0

Answer:

3000 kg meter per sec

Explanation:

Momentum of an object refers the motion of an object. Momentum depends upon mass and velocity both.

Formula to calculate the momentum of any object is,

Momentum = Mass × Velocity

By substituting values of mass and velocity of the shark from the question,

Momentum of shark = 200 × 15

                                  = 3000 kg meter per second

Therefore, shark weighing 200 kg has the momentum as 3000 kg meter per seconds.

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What is the magnetic force on a 200 cm length of (straight) wire carrying a current of 30 A in a region where a uniform magnetic
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Answer:

F = 0.112 N

Explanation:

To find the magnitude of magnetic force on the wire, you use the following formula:

|\vec{F}|=|i\vec{L}\ X\ \vec{B}|=iLBsin\theta   (1)

L: length of the wire = 200cm = 0.2m

i: current in the wire = 30 A

B: magnitude of the magnetic field = 0.055 T

θ: angle between the directions of L and B = 20°

You replace the values of L, i, B and θ in the equation (1):

|\vec{F}|=(30A)(0.2m)(0.055T)sin(20\°)=0.112N

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The small spherical planet called "Glob" has a mass of 7.88×10^18 kg and a radius of 6.32×10^4 m. An astronaut on the surface of
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Answer: The small spherical planet called "Glob" has a mass of 7.88×1018 kg and a radius of 6.32×104 m. An astronaut on the surface of Glob throws a rock straight up. The rock reaches a maximum height of 1.44×103 m, above the surface of the planet, before it falls back down.

1) the initial speed of the rock as it left the astronaut's hand is 19.46 m/s.

2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.

Explanation: To find the answer, we need to know about the different equations of planetary motion.

<h3>How to find the initial speed of the rock as it left the astronaut's hand?</h3>
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                           v=\sqrt{2gh}

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                       g_g=\frac{GM}{r^2} =\frac{6.67*10^{-11}*7.88*10^{18}}{(6.32*10^4)^2}= 0.132

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                        v=\sqrt{2*0.132*1.44*10^3} =19.46 m/s

<h3>How to find the speed of the satellite?</h3>
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                       v=\sqrt{\frac{GM}{r} } =\sqrt{\frac{6.67*10^{-11}*7.88*10^{18}}{1.45*10^5} } =3.624km/s

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2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.

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