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KATRIN_1 [288]
3 years ago
6

if a 60 kg person was standing on a platform at the surface of saturn and they jumped, they would have to push with a force grea

ter than..?

Physics
1 answer:
lidiya [134]3 years ago
4 0

Answer:

A 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N

Explanation:

The gravitational attraction between an object on the surface of a planet and the planet is given by the weight of the object

Therefore the force needed to be applied for an object to lift off the surface of a planet = The weight of the object

The weight of the object on the surface of a planet = m × g

Where;

m = The mass of the object

g = The strength of gravity on the planet's surface in N/kg

The given parameters are;

The mass of the person standing on a platform at the surface of Saturn, m = 60 kg

The strength of gravity on the surface of Saturn = 9 N/kg

Therefore, we have;

The weight of the person = The force greater than which the person would have to push on the surface of Saturn so as to Jump = The weight of the person on the surface of Saturn = 60 kg × 9 N/kg = 540 N

Therefore, for a 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N.

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Alika [10]

Answer:

space , small amount of gravity is found in the space ,infact we can say that there is no gravity in the space

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2 years ago
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Who predict the black hole​
kramer

Answer:

Albert Einstein

Explanation:

He first predicted the existence of black holes in 1916

8 0
2 years ago
At what speed does a 1,248 kg compact car have the same kinetic energy as a 18,777 kg truck going 26 km/h?
notka56 [123]

The speed of car is 100.8km/h

KE =  \frac{1}{2} m(v \: truck ) {}^{2}

= 0.5 \times 18777 \times  \frac{26}{3.6} \times  \frac{26}{3.6}

= 489708.79j

=  \frac{1}{2}  \times 1248 \times( v \: car) {}^{2}

= 624v {}^{2}

so \: v {}^{2}  =  \frac{489708.7}{624}

= 784

v =  \sqrt{784}

v = 28m/s

v car= 28×3.6

=100.8km/h

Hence, the speed of the car is 100.8km/h

learn more about speed from here:

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3 0
1 year ago
A man attempts to pick up his suitcase of weight ws by pulling straight up on the handle. (See Figure 1) However, he is unable t
cupoosta [38]

Answer:

Normal force, N = W_s - F

Explanation:

Let w_s is the weight of suitcase. A man attempts to pick up his suitcase by pulling straight up on the handle. The weight of the suitcase in downward direction. The normal force is acting in upward direction. Let F is the force with which it is pulled straight up.

So, the normal force is given by :

N = W_s - F

N = mg - F

mg is the weight of the suitcase.

Hence, this is the required solution.

3 0
3 years ago
A(n) 14 g bullet is fired into a(n) 121 g block of wood at rest on a horizontal surface and stays inside. After impact, the bloc
kotegsom [21]

Answer:

33.14 m/s

Explanation:

The mass of the block is 121g or .121 kg. As the bullet is lodged in the block the total mass is 121+14 = 135 g or 0.135 kg.

The frictional force that makes the block come to a stop is normal force* coefficient of friction = 0.135 * 9.8 * 0.7 = 0.9261 N

As the block comes to rest after sliding for 8.3 meters the energy it was given by the bullet is

0.135 * 9.8 * 0.7 * 8.3

= 7.69 Nm

Now this energy is provided the bullet. So the energy in the bullet was equal to

1/2 * mv² = 0.5 * 14 * v².

0.5 * 0.014 * v^2 = 0.135 * 9.8 * 0.7 * 8.3 = 7.69

=> 0.007 * v² = 7.69

=> v² = 7.69 / 0.007

=> v² = 1098.57

=> v = √1098.57

=> v = 33.14 m/s

8 0
3 years ago
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