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drek231 [11]
2 years ago
9

Tiny mass of 67kg and tubby mass of 83 kg are now on the opposite ends of a see saw and are both 1.4m from the balance point whe

re should their sister teeny whose mass is 32 kg sit so the see saw balances
Physics
1 answer:
Fittoniya [83]2 years ago
6 0

Answer:

0.7 m between the balance point and Tiny

Explanation:

It's intuitive to say she sould be on the side the smaller mass is placed. How far from the balance point?

Let's call x that distance. and assume that the contraption is "oriented" so that being on the side with tiny (and teeny) gives you a positive distance from the balance point, and negative on the other side.

At equilibrium, the sum of all momentums (momenta?) will be zero:

67\times 1.4 +32\times x + 83 \times (-1.4) = 0\\32x -16(1.4) = 0 \rightarrow 2x=1.4 x= 0.7

In layman's term, she has to be halfway between the balance point and Tiny.

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saw5 [17]

Answer:

SpongeBob SquarePants

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3 years ago
A futuristic design for a car is to have a large solid disk-shaped flywheel within the car storing kinetic energy. The uniform f
Aleks04 [339]
A futuristic design for a car is to have a large solid disk-shaped flywheel within the car storing kinetic energy. The uniform flywheel has mass 370 kg with a radius of 0.500 m and can rotate up to 320 rev/s. Assuming all of this stored kinetic energy could be transferred to the linear velocity of the 3500-kg car, find the maximum attainable speed of the car.
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3 years ago
What do we call the small changes that
Lelu [443]

Answer:

The "butterfly Effect"

Explanation:

The "butterfly effect" will probably have big changes in the future.

6 0
2 years ago
A rotating fan completes 1200 revolutions every minute. Consider the tip of a blade, at a radius of 0.15 m. (a) Through what dis
olga55 [171]

Answer:

(a) 0.942 m

(b) 18.84 m/s

(c) 2366.3 m/s²

(d) 0.05 s

Explanation:

(a) In one revolution, it travels through one circumference, 2πr = 2 × 3.14 × 0.15 m = 0.942 m.

(b) Its frequency, f, is 1200 rev/min = \dfrac{1200}{60}rev/s = 20 rev/s.

Its angular frequency, ω = 2πf = 2π × 20 = 40π

The speed is given by

v = ωr = 40π × 0.15 = 6π = 18.84 m/s

(c) Its acceleration is given by, a = ω²r = (40π)² × 0.15 = 2366.3 m/s²

(d) The period is the inverse of the frequency because it is the time taken to complete one revolution.

T = \dfrac{1}{f}

T = 1/20 = 0.05 s

6 0
3 years ago
Consider the standing wave pattern below created by a string fixed at both ends. The string is under a tension of 0.98 N and has
Shalnov [3]

Answer:

11.07Hz

Explanation:

Check the attachment for diagram of the standing wave in question.

Formula for calculating the fundamental frequency Fo in strings  is V/2L where;

V is the velocity of the wave in string

L is the length of the string which is expressed as a function of its wavelength.

The wavelength of the string given is 1.5λ(one loop is equivalent to 0.5 wavelength)

Therefore L = 1.5λ

If L = 3.0m

1.5λ = 3.0m

λ = 3/1.5

λ = 2m

Also;

V = √T/m where;

T is the tension = 0.98N

m is the mass per unit length = 2.0g = 0.002kg

V = √0.98/0.002

V = √490

V = 22.14m/s

Fo = V/2L (for string)

Fo = 22.14/2(3)

Fo = 22.14/6

Fo = 3.69Hz

Harmonics are multiple integrals of the fundamental frequency. The string in question resonates in 2nd harmonics F2 = 3Fo

Frequency of the wave = 3×3.69

Frequency of the wave = 11.07Hz

3 0
3 years ago
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