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Leona [35]
3 years ago
10

How can the direction of a tensional force be changed without diminishing the force?

Physics
1 answer:
RSB [31]3 years ago
4 0

Given what we know, we can confirm that the tensional force of a system can in theory be changed without diminishing its force through the use of an ideal pulley.

<h3>What is an ideal pulley?</h3>
  • A pulley is a small wheel through which a string or chain is run.
  • These are used in order to change the direction of a force.
  • An ideal pulley would be one in which there is no friction and the pulley itself would have no mass.
  • Therefore, the force would be able to change directions without giving part of its force to the pulley system.

Therefore, we can confirm that the only known way to change the direction of a force without diminishing its value would be through the use of a frictionless and massless pulley system otherwise known as an ideal pulley.

To learn more about Friction visit:

brainly.com/question/13357196?referrer=searchResults

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Who has the best answer for this
ioda

Answer:

electricity because it has more percentage nd energy

Explanation:

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6 0
2 years ago
Magnetism produced by electric current is known as...............
Triss [41]
I believe it is an electromagnet
3 0
3 years ago
When a 1.0-kilogram cart moving with a speed of 0.50 meter per second on a horizontal surface collides with a second 1.0-kilogra
yanalaym [24]

The speed of the combined carts after the collision is 0.25 m/s

Explanation:

We can solve this problem by using the principle of conservation of momentum. In fact, the total momentum of the system must be conserved before and after the collision, so we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v

where:

m_1 = 1.0 kg is the mass of the first cart

u_1 = 0.50 m/s is the initial velocity of the first cart

m_2 = 1.0 kg is the mass of the second cart

u_2 = 0 is the initial velocity of the second cart

v is the final combined velocity of the two carts

Re-arranging the equation and substituting the values, we find: the final velocity:

v=\frac{m_1 u_1}{m_1+m_2}=\frac{(1.0)(0.50)}{1.0+1.0}=0.25 m/s

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4 0
4 years ago
An electron de-excites from the fourth quantum level to the third and then directly to the first. Two frequencies of light are e
4vir4ik [10]

Answer:

The answer is explained below.

Explanation:

The energy emitted during the de-excitation of an electron from a higher energy level to a lower energy level is directly proportional to the frequency of the emitted light.

Here, the total sum of the energies of 2 frequencies of light emitted in different stages is equal to the energy of a single frequency of light during the de-excitation of fourth level to ground level directly.

Hence the total sum of of the frequencies of 2 lights emitted in different stages is equal to the frequency of single frequency of light emitted during the de-excitation  from fourth level to ground level directly.

The some of the energies of 2 frequencies emitted by one electron is equal to the energy of a single frequency when electron jumps directly.

6 0
3 years ago
A stick of length 1.3 m is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other en
soldi70 [24.7K]

Answer:

Vf = 5.05 m/s

Explanation:

To know this, you need to use the expressions for free fall.

In this case, we only know the length of the stick which is 1.3 m.

The stick is held vertically and then is allowed to fall freely. Now, we want to know the final speed of the stick when it reach the floor.

In this case, we can assume that when the stick is allowed to fall, the innitial speed is 0. Then, the other thing we can assume is the height where the stick is put to fall. In this case, the height is the same as the length, because the stick is already on the floor but is standing vertically.

So, we have here the height, and if the stick is falling, is because of gravity, which is 9.8 m/s²

To calculate the speed, you can use this expression:

Vf = √2*g*h

Replacing the data we have:

Vf = √2 * 9.8 * 1.3

Vf = 5.05 m/s

3 0
3 years ago
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