Answer:
![\large \boxed{\text{-2043.96 kJ/mol}}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5Ctext%7B-2043.96%20kJ%2Fmol%7D%7D)
Explanation:
Assume the reaction is the combustion of propane.
Word equation: propane plus oxygen produces carbon dioxide and water
Chemical eqn: C₃H₈(g) + O₂(g) ⟶ CO₂(g) + H₂O(g)
Balanced eqn: C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)
(a) Table of enthalpies of formation of reactants and products
![\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{C$_{3}$H$_{8}$(g)} & -103.85 \\\text{O}_{2}\text{(g)} & 0 \\\text{CO}_{2}\text{(g)} & -393.51 \\\text{H$_{2}$O(g)} & -241.82\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcc%7D%5Ctextbf%7BSubstance%7D%20%26%20%5Ctextbf%7B%24%5CDelta_%7B%5Ctext%7Bf%7D%7D%24H%2F%28kJ%2Fmol%7D%29%20%5C%5C%5Ctext%7BC%24_%7B3%7D%24H%24_%7B8%7D%24%28g%29%7D%20%26%20-103.85%20%5C%5C%5Ctext%7BO%7D_%7B2%7D%5Ctext%7B%28g%29%7D%20%26%200%20%5C%5C%5Ctext%7BCO%7D_%7B2%7D%5Ctext%7B%28g%29%7D%20%26%20-393.51%20%5C%5C%5Ctext%7BH%24_%7B2%7D%24O%28g%29%7D%20%26%20-241.82%5C%5C%5Cend%7Barray%7D)
(b)Total enthalpies of reactants and products
![\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)\\= \text{-2147.81 kJ/mol - (-103.85 kJ/mol)}\\= \text{-2147.81 kJ/mol + 103.85 kJ/mol}\\= \textbf{-2043.96 kJ/mol}\\\text{The enthalpy change is $\large \boxed{\textbf{-2043.96 kJ/mol}}$}](https://tex.z-dn.net/?f=%5CDelta_%7B%5Ctext%7Brxn%7D%7DH%5E%7B%5Ccirc%7D%20%3D%20%5Csum%20%5Cleft%28%20%5CDelta_%7B%5Ctext%7Bf%7D%7D%20H%5E%7B%5Ccirc%7D%20%5Ctext%7Bproducts%7D%5Cright%29%20-%20%5Csum%20%5Cleft%20%28%5CDelta_%7B%5Ctext%7Bf%7D%7DH%5E%7B%5Ccirc%7D%20%5Ctext%7Breactants%7D%20%5Cright%29%5C%5C%3D%20%5Ctext%7B-2147.81%20kJ%2Fmol%20-%20%28-103.85%20kJ%2Fmol%29%7D%5C%5C%3D%20%20%5Ctext%7B-2147.81%20kJ%2Fmol%20%2B%20103.85%20kJ%2Fmol%7D%5C%5C%3D%20%5Ctextbf%7B-2043.96%20kJ%2Fmol%7D%5C%5C%5Ctext%7BThe%20enthalpy%20change%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B-2043.96%20kJ%2Fmol%7D%7D%24%7D)
ΔᵣH° is negative, so the reaction is exothermic.
The formula to be used for this problem is as follows:
E = hc/λ, where h is the Planck's constant, c is the speed of light and λ is the wavelength. Also 1 aJ = 10⁻¹⁸ J
0.696×10⁻¹⁸ = (6.62607004×10⁻³⁴ m²·kg/s)(3×10⁸ m/s)/λ
Solving for λ,
λ = 2.656×10⁻⁷ m or <em>0.022656 nm</em>
230,000. and that weird u
hope this helps
Answer:
In a nuclear fusion reaction, the nuclei of two atoms combine to create a new atom. Most commonly, in the core of a star, two hydrogen atoms fuse to become a helium atom. Although nuclear fusion reactions require a lot of energy to get started, once they are going they produce enormous amounts of energy.
Explanation: