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meriva
3 years ago
5

How many moles of N 2 make 1.76 moles of NH 3 ? do you need to. Please help me!

Chemistry
1 answer:
katrin [286]3 years ago
3 0
I don’t quite understand this one sorry
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All solutions<br>are mixtures; but<br>all mixtures are<br>not solutions.<br>why?​
aleksklad [387]

All solutions are mixtures of two or more substances, but unless the mixture has a homogeneous distribution of solutes in the solvent, then the mixture is not a solution. Therefore, all mixtures are not solutions.

5 0
3 years ago
What is the concentration of a solution that has 15.0 g NaCl dissolved to a total of 750 ml?
Oksana_A [137]

<u>Answer:</u> The concentration of solution is 0.342 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (Sodium chloride) = 15 g

Molar mass of sodium chloride = 58.5 g/mol

Volume of solution = 750 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{15g\times 1000}{58.5g/mol\times 750mL}\\\\\text{Molarity of solution}=0.342M

Hence, the concentration of solution is 0.342 M

6 0
3 years ago
Which phrase best describes the bond in H2?
Gala2k [10]

Answer and Explanation:

Two hydrogen atoms, each containing one electron, approach each other in the formation of a molecule of hydrogen. Each atom needs a total of two electrons to fill their outermost energy level and make them stable. The best choice is to share their single electrons. Hence, a pair of bonding electrons is shared between the hydrogen atoms in the molecules.

This constitutes a single covalent bond. Hence, the correct option is B)

6 0
3 years ago
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The _______ force between each planet and the Sun keeps the planets in orbit around the Sun.
finlep [7]

Answer:

The <u>Force of Gravity</u>  force between each planet and the Sun keeps the planets in orbit around the Sun.

Explanation:

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3 years ago
What volume will 0.875 moles of Kr occupy at STP
umka21 [38]

<span> </span> <span>V = nRT/P = (0.875)(0.082057)(273)/(1) = 19.6 L</span>

6 0
3 years ago
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