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Len [333]
3 years ago
5

Which statement best describes the energy of activation?

Chemistry
2 answers:
Furkat [3]3 years ago
6 0

activation energy start off chemical reaction

iren [92.7K]3 years ago
4 0

Answer:

Explanation:

it is more quickly overcome when the temperature increases

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Yes, Yes it is. Food coloring has chemicals in it
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Which is an unnecessary rule for writing chemical formulas?
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identify the positive ion and charge
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What is true of a substance with a lot of mass?
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A. it contains a lot of matter

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2 years ago
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A reaction mixture initially contains 0.140 MCO and 0.140 MH2O. What will be the equilibrium concentration of CO?
Allushta [10]

Answer:

0.013 M

Explanation:

From the question, we can make the following deductions; we are given mixture that contains two compounds, that is A and B, 0.140 M CO and 0.140 M H2O respectively. Then, we are asked to find the equilibrium concentration of Carbonmonoxide,CO.

So, the equation for the reaction is given below;

CO + H2O <-----------------> CO2 + H2.

Initially: we have 0.14M of CO, 0.14M of H2O and zero (0) concentration of CO2 and H2.

At time,t = CO =0.14 - x , H2O = 0.14 - x, CO2 and H2 = x.

The above reaction consist of the forward reaction and the backward reaction.

Therefore, the equilibrium Concentration of CO;

(Since we are giving that Kc = 102). Then, Kc=  [CO2][H2] ÷ [CO][H2O]. Where Kc is the equilibrium constant.

Therefore, 102 = [x^2] / [0.14 - x]^2.

==> 10.1= x/0.14 - x.

====> 0.141 - 10.1 x = x.

x + 10.1 x = 0.141.

===> 11.1 x = 0.141.

===> x = 0.141 ÷ 11.1.

===> x = 0.127 M .

Then, at time,t CO = 0.14 - x.

= 0.14 - 0.127 = 0.013 M

8 0
3 years ago
Read 2 more answers
Hãy tìm công thức hóa học của những oxit có thành phần khối lượng như sau S:50%; C:42,8%; Mn:49,6%; Pb:86,6%
Novosadov [1.4K]

Answer:

Find the chemical formulas of oxides that contain the following composition:

S:50%; C:42,8%; Mn:49,6%; Pb:86,6%

Explanation:

In the given oxide of sulphur,

50%S is present that means remaining 50% is O.

Divide the % with atomic mass:

S                                     O

50/32= 1.5625            50/16=3.125

divide with smallest ratio:

1.5625/1.5625=1              3.125/1.5625=2

Hence, the formula of oxide is SO_2.

Similarly:

Carbon is 42.8% means the reamining % will be O that is 57.2%.

C                                                    O

42.8/12=3.575                         57.2/16=3.575

Divide with smallest ratio:

3.575/3.575=1                            3.575/3.575=1

Hence, the formula of oxide is CO.

Mn is 49.6% means the remining is % is O that is 50.4%.

First divide with atmic mass of respective element, then get the smallest ratio.

That gives the mole ratio of each constituent atom.

Mn                                 O

49.6/55.0=0.90            50.4/16=3.15

0.90/0.90=1                   3.15/0.90=3.5

Multiply with two

2                                        7

Hence, the formula becomes:

Mn_2O_7

Pb is 86.6% means ---remaining 13.4% is O.

Pb                                               O

86.6/207 = 0.418 mol                13.4/16=0.85

0.418/0.418=1                               0.85/0.418=2.0

Hence, the formula is:PbO_2  

   

3 0
2 years ago
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