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2 years ago

BRAINLIEST IF CORRECT, NO LINKS OR SPAM ALLOWED

Mathematics

1 answer:

ahrayia [7]2 years ago

7 0

Answer:

b: 100

c:yes

d: younger, more, small/younger

Step-by-step explanation:

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Solve 5x - 3y = 9 for y.

LenKa [72]

5x - 3y = 9
5x = 9 + 3y
5x - 9 = 3y
( 5x - 9 ) / 3 = y
y = ( 5 / 3x ) - ( 9 / 3 ) ( I just split the common denominator to individual parts )
y = 5 / 3x - 3

8 0

3 years ago

Maria handed out 125 flyers that gave students the time and locationtry outs for the school volleyball team. What is 125 written

Temka [501]

One way is to factor and see which ones repeat

125=5*5*5
it is 5 times itself 3 times
5^3

4 0

3 years ago

Read 2 more answers

What is the value of the expression 5/7 divided by 8/9

kirill115 [55]

45/56
5/7 divided 8/9
5/7 times 9/8
45/56

7 0

3 years ago

A researcher computes the following 2 x 3 between-subjects ANOVA, in which 11 participants were observed in each group. Which ef

pishuonlain [190]

Answer:

D. There were no significant effects.

Step-by-step explanation:

The table below shows the representation of the significance level using the two-way between subjects ANOVA.

Source of Variation SS df MS F P-value

Factor A 10 1 10 0.21 0.660

Factor B 50 2 25 0.52 0.6235

A × B 40 2 20 0.42 0.6783

Error 240 5 48 - -

Total 340 10 - - -

From the table above , the SS(B) is determined as follows:

SS(B) = SS(Total)-SS(Error-(A×B)-A)

= 340-(240-40-10)

= 50

A researcher computes the following 2 x 3 between-subjects ANOVA;

k=2

n=3

N(total) = no of participants observed in each group =11

df for Factor A= (k-1)

=(2-1)

df for Factor B = (n-1)

=(3-1)

df for A × B

= 2 × 1

= 2

df factor for total

=(N-1)

=11-1

=10

MS = SS/df

Thus, from the table, the P-Value for all data is greater than 0.05, therefore we fail to reject H₀.

4 0

3 years ago

Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$

Viefleur [7K]

QUESTION 1

Given that:

$f(x)=2x^2+3x-9$ ,

$g(x)=5x+11$ ,

and

$h(x)=-3x^2+1$

Then;

$f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)$

$f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1$

Group similar terms;

$f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1$

Simplify;

$f(x)-g(x)+h(x)=-x^2-2x-19$

QUESTION 2

Given that;

$f(x)=4x-7$ .

$g(x)=(x+1)^2$

and

$s(x)=f(x)+g(x)$

Substitute the functions;

$s(x)=4x-7+(x+1)^2$

Substitute x=3

$s(3)=4(3)-7+(3+1)^2$

$s(3)=12-7+(4)^2$

$s(3)=5+16$

$s(3)=21$

QUESTION 3

Given:

$f(x)=3x+2$

$g(x)=x^2-5x-1$

$f(g(x))=f(x^2-5x-1)$

This implies that;

$f(g(x))=3(x^2-5x-1)+2$

Expand the parenthesis;

$f(g(x))=3x^2-15x-3+2$

$f(g(x))=3x^2-15x-1$

QUESTION 4

The given function is;

$f(x)=3(x-6)^2+1$

Let

$y=3(x-6)^2+1$

$\Rightarrow y-1=3(x-6)^2$

$\Rightarrow \frac{y-1}{3}=(x-6)^2$

$\Rightarrow \sqrt{\frac{y-1}{3}}=x-6$

$\Rightarrow x=6+\sqrt{\frac{y-1}{3}}$

The range is:

$\frac{y-1}{3}\ge0$

$y-1\ge0$

$y\ge1$

The interval notation is;

$[1,+\infty)$

6 0

3 years ago