Answer:
234.35 °C
Explanation:
Given data:
Volume of balloon = 125000 mL
Moles of oxygen = 3 mol
Pressure = 1 atm
Temperature = ?
Solution:
Formula:
PV = nRT
P = Pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
Volume of balloon = 125000 mL × 1 L /1000 mL
Volume of balloon = 125 L
Now we will put the values:
Ideal gas constant = R = 0.0821 atm.L/mol.K
PV = nRT
T = PV/nR
T = 1 atm × 125 L/ 0.0821 atm.L/mol.K × 3 mol
T= 125 /0.2463 /K
T = 507.5 K
K to °C
507.5 K - 273.15 = 234.35 °C
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Given:
12.0 M HCl
2.0 liters of a 3.0 M HCl
Required:
volume of concentrated hydrochloric acid
Solution:
M1V1 = M2V2
(12.0 M HCl)V1 = (3.0 M HCl)( 2.0 liters)
V1 = (3.0 M HCl)( 2.0 liters)/ (12.0
M HCl)
V1 = 0.5 liters
Answer:
Explanation:
Total pressure of the mixture = 300 mm Hg
equation of reaction
C₇ H₁₆(g) + 11 O₂ (g) → 7 CO₂(g) + 8 H₂O(g)
partial pressure of heptane = mole fraction heptane × total pressure = 1 / 12 × 300 mm Hg = 25 mm Hg
partial pressure of oxygen = mole fraction oxygen × total pressure = 11 / 12 × 300 mm Hg = 275 mm Hg
After the reaction
total number of mole before the reaction = 12
total number of mole after the reaction = 15
temperature and volume did not change
if 12 to 300 mm Hg
15 will be 15 × 300 / 12 = 375 mm Hg
partial pressure of water vapor = mole fraction of water vapor × 375 mm Hg = 8 / 15 × 375 mm Hg = 200 mm Hg
The liter is the base metric unit for measuring volume