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iris [78.8K]
3 years ago
10

Using the complex based titration system: 50.00 mL 0.00250 M Ca2+ titrated with 0.0050 M EDTA, buffered at pH 11.0 determine (i)

first pCa first before initiating the titration process and then (ii) at equivalence when all the Ca2+ is titrated to CaY2-. Please, use your text books and/or lecture notes to find potentially missing information about constants needed to solve the problem.
Chemistry
1 answer:
gogolik [260]3 years ago
4 0

Answer:

i) The pCa before initiating the titration is 2.6

ii) The pCa is 6.67

Explanation:

please look at the solution in the attached Word file

Download docx
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The atomic radius of main group elements generally increases down a group because
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The atomic radius of main group elements generally increases down a group because as there are more electrons they are farther away from the nucleus and the electrons closer to the nucleus shield the outer electrons from the protons for attraction.

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The solvent in a solution evaporates out over time, leaving behind the solute.
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Answer:

When a solution is heated, the solvent evaporates, leaving behind the dissolved solids as residue. When a solution containing dissolved solutes is heated, the solvent will evaporate.

Explanation:

. P.S. Evaporation to dryness cannot be use for solutions like sugar solution because the sugar will decompose upon heating.

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Why would scientists use a spectrometer in space.
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Answer:

A. To study the chemical composition of the surface of a planet

Explanation:

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Al(s) + NiSO4(aq)<br> Balance
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Answer:

2Al(s) + 3NiSO4 --> Al2(SO4)3 + 3Ni

Explanation:

This reaction type is a single replacement. The format of a single replacement is:

A+BC --> B+AC

A= Al

B= Ni

C= SO

The coefficient 3 for Ni would become a subscript for  AC. After you plug those into the reaction you need to count how many of each are on the left side and try to get the same number on the right side. Both sides must be equal to have a balanced equation.

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3 years ago
The complete combustion of propane (C3H8) in the presence of oxygen yields CO2 and H2O: C3H8 (g) + 5O2 (g) 3CO2 (g) + 4H2O (g) a
mixas84 [53]

Answer:

26.9 L is the volume of CO₂, we obtained

Explanation:

The reaction is: C₃H₈(g) + 5O₂(g)  →  3CO₂ (g) + 4H₂O (g)

Let's determine the reactants moles:

27.5 g . 1mol / 44 g = 0.625 moles

We need density of O₂ to determine mass and then, the moles.

O₂ density = O₂ mass / O₂ volume

O₂ density . O₂ volume = O₂ mass

1.429 g/L . 45L = O₂ mass → 64.3 g

Moles of O₂ → 64.3 g . 1mol/32g = 2.009 moles

Let's find out the limiting reactant:

1 mol of propane needs 5 moles of oxygen to react

Then, 0.625 moles will react with (0.625 . 5)/1 = 3.125 moles of O₂

Oxygen is the limiting reactant, we need 3.125 moles but we only have 2.009 moles

Ratio is 5:3. 5 moles of O₂ produce 3 moles of CO₂

Therefore, 2.009 moles of O₂ must produce (2.009 .3) /5 = 1.21 moles of CO₂. Let's find out the volume, by Ideal Gases Law (STP are 1 atm and 273K, the standard conditions)

1 atm . V = 1.21 moles . 0.082 . 273K

V = (1.21 moles . 0.082 . 273K) / 1atm = 26.9 L

3 0
3 years ago
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