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Ilia_Sergeevich [38]
3 years ago
5

What is the final concentration if water is added to 0.50 L of a 12 M NaOH solution to make 3.0 L of a diluted NaOH solution?

Chemistry
2 answers:
Kisachek [45]3 years ago
6 0

Answer:

2 M NaOH solution

Explanation:

Initial concentration of NaOH = 12 M

Initial volume of solution = 0.5

Initial number of moles = Molarity×Volume = 12×0.5 = 6 moles

Note: On dilution the number of moles does not change.

Initial number of moles = final number of moles.

Final number of moles = 6 moles

Final volume of solution = 3 L

Final concentration (in Molarity) = \frac{Final\ no\ of\ moles}{final\ volume\ in\ L}=\frac{6}{3}= 2\ M

SVETLANKA909090 [29]3 years ago
3 0

Answer:

The answer to your question is the second option: 2M NaOH solution

Explanation:

Data

Volume 1 = 0.5 l

Concentration 1 = 12 M NaOH

Volume 2 = 3 l

Concentration 2 = ?

Formula

                     V₁C₁  =  V₂C₂

Solve for C₂

                     C₂ = V₁C₁ / V₂

Substitution

                    C₂ = (0.5)(12) / 3

Simplification and result

                    C₂ = 6 / 3

                    C₂ = 2 M  

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Determine the mass of CuSO4 • 5H20 that must be used to prepare 250mL of 2.01 M CuSO4(aq).
mario62 [17]

Given parameters:

Volume of CuSO₄ = 250mL

Concentration of CuSO₄ = 2.01M

Unknown:

Mass of CuSO₄.5H₂O = ?

To solve this problem, we must write the chemical relationship between both species.;

             CuSO₄.5H₂O  →   CuSO₄ + 5H₂O

Now that we know the expression, it is possible to solve for the unknown mass.

First find the number of moles of CuSO₄;

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Take 250mL to L so as to ensure uniformity of units;

           Volume  = 250 x 10⁻³L

  Input the parameters and solve for number of moles;

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From the equation;

             1 mole of CuSO₄ is produced from 1 mole of CuSO₄.5H₂O  

So  0.5 moles of CuSO₄ will be produced from 0.5 moles of CuSO₄.5H₂O

Now let us find the molar mass of CuSO₄.5H₂O = 63.6 + 32 + 4(16) + 5(2x1 + 16)  = 249.6g/mole

Mass of CuSO₄.5H₂O = number of moles x molar mass

                                      = 0.5 x 249.6

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5 0
3 years ago
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Total ATP molecules produced = 13.5 + 47.5 + 5

Total ATP molecules produced = 66 molecules of ATP

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