All categories

3 years ago

What is the final concentration if water is added to 0.50 L of a 12 M NaOH solution to make 3.0 L of a diluted NaOH solution?

Chemistry

2 answers:

Kisachek [45]3 years ago

6 0

Answer:

2 M NaOH solution

Explanation:

Initial concentration of NaOH = 12 M

Initial volume of solution = 0.5

Initial number of moles = Molarity×Volume = 12×0.5 = 6 moles

Note: On dilution the number of moles does not change.

Initial number of moles = final number of moles.

Final number of moles = 6 moles

Final volume of solution = 3 L

Final concentration (in Molarity) = $\frac{Final\ no\ of\ moles}{final\ volume\ in\ L}=\frac{6}{3}= 2\ M$

SVETLANKA909090 [29]3 years ago

3 0

Answer:

The answer to your question is the second option: 2M NaOH solution

Explanation:

Data

Volume 1 = 0.5 l

Concentration 1 = 12 M NaOH

Volume 2 = 3 l

Concentration 2 = ?

Formula

V₁C₁ = V₂C₂

Solve for C₂

C₂ = V₁C₁ / V₂

Substitution

C₂ = (0.5)(12) / 3

Simplification and result

C₂ = 6 / 3

C₂ = 2 M

You might be interested in

Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re

borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

A + B ⇄ C

where;

numbers of moles = 0.386 mol C (g)

Volume = 7.29 L

Molar concentration of C = $\frac{0.386}{7.29}$

= 0.053 M

A + B ⇄ C

Initial 0 0 0.530

Change +x +x - x

Equilibrium x x (0.0530 - x)

$K = \frac{[C]}{[A][B]}$

where

K is given as ; 78.2 atm-1.

So, we have:

$78.2=\frac{[0.0530-x]}{[x][x]}$

$78.2= \frac{(0.0530-x)}{(x^2)}$

$78.2x^2= 0.0530-x$

$78.2x^2+x-0.0530=0$

Using quadratic formula;

$\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where; a = 78.2 ; b = 1 ; c= - 0.0530

= $\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $\frac{-b-\sqrt{b^2-4ac} }{2a}$

= $\frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$ or $\frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$

= 0.0204 or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

= 0.0530 - 0.0204

= 0.0326

Total number of moles at equilibrium = 0.0204 + 0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

$V = \frac{nRT}{P}$

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K (fixed constant temperature )

V (volume) = ???

$V=\frac{(0.0734*0.0821*273.15)}{(1.00)}$

V = 1.64604

V ≅ 1.65 L

3 0

3 years ago

How do you define medium and high level profession?according to class 8?

abruzzese [7]

Answer:

Answer: medium level profession can be defined as some one who has moved past entry level but isn't nearing the end . whereas high level profession means a person has moved past entry level and also has reached the end.

3 0

3 years ago

How many particles are in the nucleus of an atom of fluorine-19?

svetoff [14.1K]

Answer:

9 protons, 10 neutrons, and 9 electrons.

Explanation:

The particles of the nucleus of an atom of Fluorine-19 is

9 protons, 10 neutrons, and 9 electrons.

4 0

2 years ago

Read 2 more answers

What atom has the larger atomic radius Ca or Ni ?

Harrizon [31]

your answer is CA

says quizlet have and its right thanks

5 0

3 years ago

What effect did the Punic Wars have on Rome's military development? (4 points)

Doss [256]

Answer:

The correct answer is: “The Roman army grew in size and became dominant in the Mediterranean region”.

Explanation:

The Punic wars were a series of three wars that were fought between Rome and Carthage. At the end of the third war, Rome established itself as an empire, it conquered the Carthage’s empire, destroyed it completely and became the most powerful state of the Western Mediterranean.

6 0

3 years ago