Answer:
Explanation:
From the information given, by applying Kepler's 3rd law,

where;
T = period
a = semi major axis
T = 356 days (for earth)
a = 1 AU = 1.496 
Therefore, 

c = 3.9791 
However, if the body in the solar system has a period of 10.759.22 days, then, a =?
∴



![a= \sqrt[3]{2.9092 \times 10^{27}}](https://tex.z-dn.net/?f=a%3D%20%5Csqrt%5B3%5D%7B2.9092%20%5Ctimes%2010%5E%7B27%7D%7D)
a = 1.4275 
However, the velocity for a perihelion = 10.18 km/s
Using the formula
to calculate the radius, we have:
G = 
M = 
r = perihelion






Similarly, the perihelion is expressed by the equation,
r = a(1 - e)
where ;
e= eccentricity
∴




e ( eccentricity) = 0.0533
Aphelion radius in natural miles, r = a( 1+ e)


to nautical miles, we have:

radius of aphelion
nautical miles
In respect to the value of a( i.e 
the body of the solar system is Saturn