Answer:
good luck getting an answer then
Explanation:
Answer:
There is no answers given??
Explanation:
N/A
The same thing happened with my HP laptop but my dad refresh the laptop before restating it worked
Answer:
The solution is as follows.
class LFilters implements Lock {
int[] lvl;
int[] vic;
public LFilters(int n, int l) {
lvl = new int[max(n-l+1,0)];
vic = new int[max(n-l+1,0)];
for (int i = 0; i < n-l+1; i++) {
lvl[i] = 0;
}
}
public void lock() {
int me = ThreadID.get();
for (int i = 1; i < n-l+1; i++) { // attempt level i
lvl[me] = i;
vic[i] = me;
// rotate while conflicts exist
int above = l+1;
while (above > l && vic[i] == me) {
above = 0;
for (int k = 0; k < n; k++) {
if (lvl[k] >= i) above++;
}
}
}
}
public void unlock() {
int me = ThreadID.get();
lvl[me] = 0;
}
}
Explanation:
The code is presented above in which the a class is formed which has two variables, lvl and vic. It performs the operation of lock as indicated above.
=A2*D2
The above formula will allow calculation of monthly cost of the first raw material.This is done by Multiplying the contents of cell A2 (Column A, Row 2) and cell D2 (Column D, Row 2). Here Cell A2 contains cost of the first raw material and Cell D2 contains number of units of the raw material produced each month. After finding the monthly cost of the first raw material in this way, the monthly cost of other raw materials can simply be calculated by dragging down the formula to apply to the rows below.