Ask question

Ask question

All categories

2 years ago

12

Calculate the magnitude of the gravitational force between Goku with a mass of 62 kg and King Kai’s planet with a mass of 1.458x

1015 kg if the distance between their centers of mass is 31 m.

1 answer:

Brilliant_brown [7]2 years ago

7 0

Answer:

6227.866 N

Explanation:

F = G . m(goku) . m(planet) / d²

F = 6.674 x 10-¹¹ x 62 x 1.458 . 10¹⁵ / 31²

F = 6227.866 N

You might be interested in

A red car passes a blue car. Which is true?

Marrrta [24]

D. The red car is moving faster than the blue car

4 0

3 years ago

Gaining neutrons makes an element?

Kobotan [32]

Answer:

C. Have no change in electrical charge

Explanation:

If a element gains neutron it become an Isotope. The electrical charge do not change for this, only the atomic mass changes when an element gains neutrons.

The electrical charge is affected when there is a variation in the number of electrons or protons in the element.

6 0

3 years ago

A vector has what and direction

galben [10]

A vector Quantity has MAGNITUDE and direction, so the ‘what’ is Magnitude.

8 0

3 years ago

Read 2 more answers

If the frequency of this beam is increased while the intensity is held constant, does the number of electrons ejected per second

Ivan

Answer:

if the intensity of photons is constant then number of ejected electrons will remain same

Explanation:

As per photoelectric effect we know that when light of sufficient frequency fall on the surface of metal then electrons get ejected out of the surface with certain kinetic energy

Here the energy of photons is used to eject out the electrons from metal surface and to give the kinetic energy to the ejected electrons

so we have

$h\nu = W + KE$

here W = work function of metal which shows the energy required to eject out electrons from metal surface

KE = kinetic energy of ejected electrons

now if we increase the frequency of the photons that incident on the metal surface then in that case the incident energy will increase

So the electrons will eject out with more kinetic energy while if the number of photon is constant or the intensity of photons is constant then number of ejected electrons will remain same

8 0

3 years ago

Astronomers discover an exoplanet (a planet of a star other than the Sun) that has an orbital period of 3.87 Earth years in its

dolphi86 [110]

Answer: $4.487(10)^{11}m$

Explanation:

This problem can be solved using the Third Kepler’s Law of Planetary motion:

<em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. </em>

<em />

This law states a relation between the orbital period $T$ of a body (the exoplanet in this case) orbiting a greater body in space (the star in this case) with the size $a$ of its orbit:

$T^{2}=\frac{4\pi^{2}}{GM}a^{3}$ (1)

Where:

$T=3.87Earth-years=122044320s$ is the period of the orbit of the exoplanet (considering $1Earth-year=365days$ )

$G$ is the Gravitational Constant and its value is $6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$

$M=3.59(10)^{30}kg$ is the mass of the star

$a$ is orbital radius of the orbit the exoplanet describes around its star.

Now, if we want to find the radius, we have to rewrite (1) as:

$a=\sqrt[3]{\frac{T^{2}GM}{4\pi^{2}}}$ (2)

$a=\sqrt[3]{\frac{(122044320s)^{2}(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(3.59(10)^{30}kg)}{4\pi^{2}}}$ (3)

Finally:

$a=4.487(10)^{11}m$ This is the radius of the exoplanet's orbit

3 0

3 years ago