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Alchen [17]
3 years ago
15

Which of newtons laws is illustrated by a squid moving forward by shooting water out behind it? Why?

Physics
1 answer:
Dimas [21]3 years ago
5 0
I believe its newtons 3rd law for every action there is an equal but opposite reaction since the squid is moving foward by shooting the water its pushing the squid back as its reaction. Hope this helped !
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What likely happens to the hart rate as the cardiac mucle gets stronger
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The heart rate will likely decrease. As the cardiac muscle, or heart, gets stronger, it takes less effort to pump more blood. As a result, the heart will probably beat less, decreasing the heart rate. This is why athletes often have lower heart rates than the average person.
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Chloe is playing the flute some distance away from a crowd. If the atmospheric temperature is 15°C, what is the speed of the sou
borishaifa [10]
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7 0
3 years ago
An engine has an energy input of 125j and 35 j of that energy is transformed into useful energy
Tatiana [17]
The engine's efficiency is (35J)/125J) = 28% .

Do you have a different question to ask ?
5 0
3 years ago
An amateur astronomer looks at the moon through a telescope with a 15-cm-diameter objective. What is the minimum separation betw
Lana71 [14]

Answer:

  y = 128.0 km

Explanation:

The minimum separation of two objects is determined by Rayleygh's diffraction criterion, which establishes that two bodies are solved if the first minino of diffraction of one coincides with the central maximum of the second, with this criterion the diffraction equation remains

                       

the diffraction equation for the first minimum is

                       a sin θ = λ

In the case of circular openings, the equation must be solved in polar coordinates, leaving the expression, we use the approximation that the sine of tea is very small.

                    θ =  1.22 λ / d

                   d = 15 cm

to find the distance we can use trigonometry

             tan θ = y / L

             tan θ = sin θ / cos θ = θ

substituting

              y / L = λ / d

              y = L λ /d

let's calculate

              y = 384 10⁸ 500 10⁻⁹ / 0.15

              y = 1.28 10⁵ m

Let's reduce to km

             y = 1.28 10⁵ m (1km / 10³ m)

             y = 128.0 km

the correct answer is 120 km away

5 0
3 years ago
Near the top of the Citigroup Center building in New York City, there is an object with mass of 4.00 ✕ 105 kg on springs that ha
jasenka [17]

Explanation:

It is given that,

Mass of an object, m=4\times 10^5\ kg

(a) Time period of oscillation, T = 2.4 s

The formula for the time period of spring is given by :

T=2\pi \sqrt{\dfrac{m}{k}}

Where

k is the force constant

k=\dfrac{4\pi ^2 m}{T^2}

k=\dfrac{4\pi ^2 \times 4\times 10^5}{(2.4)^2}

k=2.74\times 10^6\ N/m

(b) Displacement in the spring, x = 2.2 m

Energy stored in the spring is given by :

U=\dfrac{1}{2}kx^2

U=\dfrac{1}{2}\times 2.74\times 10^6\ N/m\times (2.2\ m)^2

U=6.63\times 10^6\ J

Hence, this is the required solution.

7 0
3 years ago
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