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natulia [17]
3 years ago
6

Some boys and girls took part in a competition. 2/5 of the competitors were boys. 1/3 of the boys were disqualified from the com

petition. If there were 135 competitors at first, how many more girls than boys were left?
Mathematics
1 answer:
GaryK [48]3 years ago
7 0

Answer:

45

Step-by-step explanation:

According to the Question,

  • Given, Some boys and girls took part in a competition. 2/5 of the competitors were boys So 3/5 of the competitors were girls.

And there were Total 135 competitors.

So, the Number of Boys are 135 × (2/5) = 54 boys

Therefore, the Number of Girls in the competition is 135-54 = 81 Girls.

Now,

  • 1/3 of the boys were disqualified from the competition. So, 54× (1/3) = 18 boys Disqualified . the Remaining boys are 54-18 = 36 boys left in Competition.
  • Then, The number of girls more than that of boys left in competition were 81-36 = 45
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<u>Step-by-step explanation:</u>

 tanθ * cos²θ * csc²θ

=  \dfrac{sin\theta}{cos\theta} * \dfrac{cos\theta*cos\theta}{} *\dfrac{1}{sin\theta*sin\theta}

= \dfrac{cos\theta}{sin\theta}

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<u>Step-by-step explanation:</u>

The parent graph is y = x²

The new graph y = -x² + 3 should have the following:

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Answers:

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\dfrac{17\pi}{6} - \dfrac{12\pi}{6} = \dfrac{5\pi}{6}

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b) In Quadrant 2, cos is negative and sin is positive, so tan is negative

c) \pi-\dfrac{5\pi}{6} = \dfrac{\pi}{6}

d) the reference line is above the x-axis so it is negative -->  -tan\dfrac{\pi}{6}

e) tan(\dfrac{5\pi}{6})=\dfrac{1}{-\sqrt{3}}=-\dfrac{\sqrt{3}}{3}


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3 years ago
A trust one form of holding property.
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Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1). The triangle is translated 3 units to the left and 1 unit up. What are
tankabanditka [31]

The coordinates of point B' are (-3, 6).

<h2>Given that</h2>

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).

The triangle is translated as 3 units to the left and 1 unit up.

<h3>We have to determine</h3>

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<h3>According to the question</h3>

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).

The triangle is translated as 3 units to the left and 1 unit up.

To find the coordinates of B', we will shift the x-coordinate of point B to left by 3 units and the y-coordinate of point B to 1 unit up.

After the given transformation the coordinates of point B' would be:

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