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Vitek1552 [10]
3 years ago
9

What is the empirical formula for a compound that is 7.70 % carbon and 92.3 % chlorine?

Chemistry
1 answer:
Nikolay [14]3 years ago
4 0

Answer:

Imole/C=129 Directions Show All Of Your Work For Each Of The Following Problems. 1.

Explanation:

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After fertilization, female cones become very:<br> sticky<br> light<br> O hard
S_A_V [24]

Answer:

light

Explanation:

sorry don't now this one

8 0
3 years ago
What type(s) of bonding would be expected for each of the following materials: brass (a copper-zinc alloy), rubber, barium sulfi
mr_godi [17]

The force of attraction that results in holding of atoms or ions together in a molecule or crystal is said be bonding.  Bond formation can take place by either attraction or transfer of electrons. There are single, double, and triple bonds.  There are many types of bonding namely:

Covalent (sharing of electrons takes place).

Ionic (transfer of electrons takes place).

Metallic (ionized atoms of metals and the sea of electrons around them).

  • Brass (a copper-zinc alloy)

Brass is an alloy of metal that is copper and zinc. Hence, the metallic bonding is present in the brass.

  • Rubber

It is a polymer whose monomer unit is isoprene, which is a covalent compound. The isoprene units are attached in repeated units to form rubber by covalent bonding.

  • Barium sulfide (BaS)

Due to the large electronegativity difference between barium and sulfur, barium sulfide is an ionic compound. Thus, ionic bonding is present in barium sulfide.

  • Solid xenon

Only xenon atoms are present in solid xenon which are interacted by weak Van der Waal's interactions.

  • Bronze

Bronze is an alloy of metal that is copper and tin. Hence, the metallic bonding is present in the brass.

  • Nylon

It is a polymer whose monomer unit is caprolactam, which is a covalent compound. The caprolactam units are attached in repeated units to form nylon by covalent bonding.

  • Aluminum phosphide (AlP)

Aluminum phosphide is a covalent compound and thus involves covalent bonding.

7 0
3 years ago
A solution is prepared by mixing 200.0 g of water, H2O, and 300.0 g of
VikaD [51]

Answer:

Mole Fraction (H₂O)  =  0.6303

Mole Fraction (C₂H₅OH)  =  0.3697

Explanation:

(Step 1)

Calculate the mole value of each substance using their molar masses.

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

200.0 g H₂O            1 mole
---------------------  x  ------------------  =  11.10 moles H₂O
                                 18.014 g

Molar Mass (C₂H₅OH): 2(12.011 g/mol) + 6(1.008 g/mol) + 15.998 g/mol

Molar Mass (C₂H₅OH): 46.068 g/mol

300.0 g C₂H₅OH              1 mole
----------------------------  x  --------------------  =  6.512 moles C₂H₅OH
                                         46.068 g

(Step 2)

Using the mole fraction ratio, calculate the mole fraction of each substance.

                                            moles solute
Mole Fraction  =  ------------------------------------------------
                               moles solute + moles solvent

                                                  11.10 moles H₂O
Mole Fraction  =  -------------------------------------------------------------
                               11.10 moles H₂O + 6.512 moles C₂H₅OH

Mole Fraction (H₂O)  =  0.6303

                                             6.512 moles C₂H₅OH
Mole Fraction  =  -------------------------------------------------------------
                               11.10 moles H₂O + 6.512 moles C₂H₅OH

Mole Fraction (C₂H₅OH)  =  0.3697

7 0
1 year ago
How many total orbitals are within the 3s 3p, and 3d sublevels of the third
vredina [299]

Answer: C

Explanation:

The one closest to the atomic center, there is a single 1s orbital that can hold 2 electrons. At the next energy level, there are four orbitals.

4 0
3 years ago
Read 2 more answers
calculate the charge on plates if the plate area is 100 cm2 , the gap between plates is 10 mm and the scale is reading 1.0 gram.
Law Incorporation [45]

Answer: The charge on the plates are 88.4 picafarad

Explanation:The equation used in measuring charge in a plate is given as:

C=Q/V =E A/D

Where E= dielectric content

A= Area of plates

d= distance between plates

Using dielectric constant for Air=8.84×10-12F/m

A=100cm2=0.01m2

d=10mm=0.001m

C= 8.84×10-12×0.01/0.001

C= 88.4 picafarad

8 0
3 years ago
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