You start by finding the mol of each
59.9g C x (mol C / 12.01 g C) = 4.98 mol C
8.06g H x (mol H / 1.00 g H) = 8.06 mol H
32.0 g O x (mol O / 16.0 g O) = 2 mol O
So when you set it up you have
C4.98 H8 O2
You divide each by the smallest mol. The smallest mol is 2
C2 H4 O2.5
However you can’t have half a mol in the empirical formula. If the value ends in 0.5, you multiply everything by 2
You’re left with
C2H8O5
The EMPIRICAL formula for lucite is C2H8O5
Note empirical is not the same as chemical formula.
In a series circuit, the sum of the voltages consumed by each individual resistance is equal to the source voltage. ... In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents flowing through each component
Answer:
all of the bad stuff such as ashes and chemicals in the air from that fire could bring bad stuff to the water
Explanation:
The answer would be a Graduated Substance, Being it describes a solution. Im not 100% sure however. Let me know how it goes.
Answer:
= - 303.975 Joules
Explanation:
Given that:
The volume of the cylinder = 0.003 m^3
Now, to liters:
The volume = 0.003 *1000 L
= 3 L
For an open cylinder, we mean the atmospheric pressure is at standard condition.
Thus, the workdone = -PΔV
= - 1 atm (3 L)
= - 3 L atm
1 L atm to Joules
= 101.325 Joules
Therefore;
=- 3* 101.325 Joules
= - 303.975 Joules
