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Temka [501]
3 years ago
15

A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,

what is the new volume of the balloon in the hot room?
Use StartFraction V subscript 1 over T subscript 1 EndFraction equals StartFraction V subscript 2 over T subscript 2 EndFraction..

2.19 L
3.33 L
3.68 L
5.60 L
Chemistry
2 answers:
Ad libitum [116K]3 years ago
8 0
The answer is 3.68 L
Bas_tet [7]3 years ago
6 0

Answer:

3.68 L

Explanation:

use charle's law formula

v1(t2) = v2(t1)

and convert celsius to kelvin k=C+273.15

3.5L(313.15K) = v2(298.15K)

solve for v2 by dividing 298.15k on both sides

v2=3.68

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What mass of water is formed when 16g of hydrogen react with excess oxygen​
artcher [175]

Hello!

To start off, we must look at atomic masses. Atoms all have different weights, so we must first find hydrogen and oxygen's atomic masses.

Oxygen: 16.00 amu

Hydrogen: 1.01 amu

Now, moving on to the weight of water itself. Water has the formula of H20, with two hydrogen atoms and one oxygen. Therefore, <u>add up the amus to get the weight of one molecule of water.</u>

1.01 + 1.01 + 16.00 = 18.02 amu

Now, to see the ratio of each component. Since hydrogen weighs a total of 2.02 amu (1.01 + 1.01) in the entire atom, we can state that hydrogen makes up about 0.112 of the weight of water. Now apply that ratio to 16 g, and solve.

0.112x = 16

142.857143 = x

So therefore, about 143 grams of water are made when 16g of hydrogen reacts with excess oxygen.

Hope this helps!

8 0
3 years ago
Read 2 more answers
During
Genrish500 [490]
If I understood question correctly,
football 1.3 • 102=132.6
Answer is 132 students participate in football.

6 0
3 years ago
___KClO3---&gt;___KCl+___O2 I need help bro.
Lina20 [59]
2 KClO3— 2 KCl + 3 O2
4 0
3 years ago
What is the total charge of all the protons in 2.2 mol of he gas?
Tasya [4]
To determine the total charge of the protons in the gas, we need to know the number of protons that are present. We use Avogadro's number to know such value. We do as follows:

2.2 mol  ( 6.022x10^23 protons / 1 mol ) = 1.325x10^24 protons

Total charge = 1.6021766208×10^−19 C (1.325x10^24) = 212262.77 C
3 0
3 years ago
consider the following equation ch4(g)+2o(g) co2(g)+2h2o(g) how many moles of oxygen are needed for the complete combustion of 3
maria [59]
The answer is 6 moles.

Since the mole ratio of ch4 to o is 1:2, and we have 3 moles of ch4, we can just multiple 3 moles by 2 and get 6 moles
3 0
3 years ago
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