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Temka [501]
3 years ago
15

A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,

what is the new volume of the balloon in the hot room?
Use StartFraction V subscript 1 over T subscript 1 EndFraction equals StartFraction V subscript 2 over T subscript 2 EndFraction..

2.19 L
3.33 L
3.68 L
5.60 L
Chemistry
2 answers:
Ad libitum [116K]3 years ago
8 0
The answer is 3.68 L
Bas_tet [7]3 years ago
6 0

Answer:

3.68 L

Explanation:

use charle's law formula

v1(t2) = v2(t1)

and convert celsius to kelvin k=C+273.15

3.5L(313.15K) = v2(298.15K)

solve for v2 by dividing 298.15k on both sides

v2=3.68

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V = m / mm  * M

V = 100 / 86.845 * 4

V = 100 / 347.38

V = 0.2875 L

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