<span>The Law of Conservation of Mass simply states
that the total amount of mass should not change in a chemical reaction that is
isolated (no other objects can enter the reaction). The total mass of the
reactants must be equal to the total mass of the products. Thus, t</span>he correct estimate of
the amount of oxygen used in the interaction is the difference between 133
g and 29 g.
The mass (g) of the original sample after decomposition is 8.3983 g.
A decomposition reaction can be described as a chemical reaction wherein one reactant breaks down into or extra merchandise.
explanation:
Reaction 2KClO₃ ⇒ 2KCl + 3O₂
moles 2 2 3
molar mass 122.55 74.55 32
Given, Mass of O₂ = 3.29g ⇒ moles of O₂
= (3.29/32) = 0.1028
3 moles of O₂ produced by 2 moles of KClO₃
Therefore, 0.1028 moles of O₂ produced by (2*0.1028/3) = 0.06853 moles of Kclo₃
Mass of KClo₃ in original sample is = moles * molar mass
= 0.06853 * 122.55
= 8.3983 g
A decomposition response occurs whilst one reactant breaks down into or extra merchandise. this may be represented through the general equation: XY → X+ Y. Examples of decomposition reactions consist of the breakdown of hydrogen peroxide to water and oxygen, and the breakdown of water to hydrogen and oxygen.
Learn more about decomposition here:-brainly.com/question/27300160
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What do you mean by not drawing?
M(O₂)=20g
M(O₂)=32.0 g/mol
n(O₂)=20/32.0=0.625 mol
m(C)=12 g
M(C)=12.0 g/mol
n(C)=12/12.0=1.0 mol
2C + O₂ → 2CO
1 mol 0.625 mol 1 mol
0.625-0.5=0.125 mol
2CO + O₂ → 2CO₂
0.250 mol 0.125 mol 0.250 mol
n(CO)=1 mol - 0.250 mol = 0.750 mol
M(CO)=28.0 g/mol
m(CO)=0.750*28.0=21.0 g
n(CO₂)=0.250 mol
M(CO₂)=44.0 g/mol
m(CO₂)=0.250*44.0=11.0 g
Answer:
6.9428 kg of CO2
Explanation:
1) Use Avogadro's number that states 1 mole = 6.022 x 10^23 particles. Convert 9.5 x 10^25 molecules into moles.
9.5 x 10^25 CO2 molecules
= 157.75 moles CO2
2) Convert 157.75 moles of CO2 into grams. CO2's molar mass is 44.01g.
= 6942.79g
3) Convert 6942.79 grams into kilograms (divide by 1000):
6.9428 kg
