Answer:
One mole of U238 ( 6.022 X 10^23 atoms) is 238 grams; one mole of U235 is 235 grams. The difference in molecular weight between a mole of U235 and U238 is 3 grams, the secret to enriching uranium.
Explanation:
Answer:
the definition of behavior is the way in which someone conducts oneself or behaves.
The mixture does not maintain a uniform composition. A homogeneous mixture really is the same anywhere you sample it, while sand generally settles out of water when given the chance and there's likely more sand at the bottom than at the top.
Given the data from the question, the number of aluminum atoms in aluminum oxide, Al₂O₃ is 2 (Option B)
<h3>Composition of aluminum oxide, Al₂O₃</h3>
From the formula of the compound, Al₂O₃ we see that the compound is composed of
<h3>How to determine the number of aluminum atoms </h3>
- Formula of compound = Al₂O₃
- Number of oxygen atoms j= 3 × 1 = 3
- Number of aluminum atoms = 2 × 1 = 2
From the above, we can conclude that Al₂O₃ contains 2 atoms of aluminum.
Learn more about mass composition:
brainly.com/question/11617445
Answer:
Kc = 4.76
Explanation:
To find the concentrations of CO and H₂ at equilibrium, you have to set up an ICE (Initial, Change, Equilibrium) table.
CO (g) + 2H₂(g) ⇌ CH₃OH (g)
I 0.32 M 0.53 M 0
C -x -2x +x
E 0.32-x 0.53-2x 0.16 M
Since you know the concentration of CH₃OH at equilibrium, it would be equal to x since 0 + x = 0.16. So,
[CH₃OH] = 0.16 M
[CO] = 0.32 - 0. 16 = 0.16 M
[H₂] = 0.53 - 2(0.16) = 0.21 M
Now that you have all the concentrations at equilibrium, you can calculate the equilibrium constant.
Kc = products ÷ reactants
= [CH₃OH] ÷ [CO][H₂]²
= 0.16 ÷ (0.16)(0.21)
Kc = 4.76
The equilibrium constant at this temperature is 4.76.
Hope this helps.
