Answer: What are the answer options?
Explanation:
I have a strange hunch that there's some more material or previous work
that goes along with this question, which you haven't included here.
I can't easily find the dates of Mercury's extremes, but here's some of the
other data you're looking for:
Distance at Aphelion (point in it's orbit that's farthest from the sun):
<span><span><span><span><span>69,816,900 km
0. 466 697 AU</span>
</span>
</span>
</span>
<span>
Distance at Perihelion
(</span></span><span>point in it's orbit that's closest to the sun):</span>
<span><span><span><span>46,001,200 km
0.307 499 AU</span> </span>
Perihelion and aphelion are always directly opposite each other in
the orbit, so the time between them is 1/2 of the orbital period.
</span><span>Mercury's Orbital period = <span><span>87.9691 Earth days</span></span></span></span>
1/2 (50%) of that is 43.9845 Earth days
The average of the aphelion and perihelion distances is
1/2 ( 69,816,900 + 46,001,200 ) = 57,909,050 km
or
1/2 ( 0.466697 + 0.307499) = 0.387 098 AU
This also happens to be 1/2 of the major axis of the elliptical orbit.
The correct formula for Ammonium oxide is (NH4)20, meaning Ammonium oxide is your answer
You may need to list your answer choices to get a specific answer.
Answer: Diagrams 3 and 4.
Explanation:
The force that one charge q1 experiences when is at a distance R of another charge q2 is:
F = k*(q1*q2)/R^2
Where k is a constant.
If this force is positive, the chares move away from each other, so if both charges are positives or both charges are negatives, then the charges move away from each other, meaning that the force is repulsive.
If the force is negative, the force is towards the other particle, then the force is attractive. This happens when one charge is positive and the other is negative.
Then the correct options are 3 and 4.