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trapecia [35]
4 years ago
5

The speed of all electromagnetic waves is 3.00 × 108 meters per second. What is the wavelength of an X-ray with a frequency of 1

.18 × 1018 Hz?
2.54 × 1026 meters
3.93 × 109 meters
2.54 × 10-10 meters
3.93 × 10-11 meters
Physics
2 answers:
Ierofanga [76]4 years ago
8 0
The answer is......2.54x10^-10......
Akimi4 [234]4 years ago
8 0

Explanation :

Given that,

The speed of all electromagnetic waves is, v=3\times 10^8\ m/s

Frequency of x-ray,\nu=1.18\times 10^{18}\ Hz

The speed of the wave is defined as the product of the frequency and the wavelength.

\lambda=\dfrac{v}{\nu}

\lambda=\dfrac{3\times 10^8}{1.18\times 10^{18}}

\lambda=2.54\times 10^{-10}\ m

So, the correct option is (c).

Hence, this is the required solution.

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Differentiate the following functions with respect to x <br>xsin x​
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Answer:

Here is your answer

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3 years ago
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German physicist Werner Heisenberg related the uncertainty of an object's position (Δx) to the uncertainty in its velocity (Δ???
fredd [130]

Answer:

\Delta x = 5.47 \times 10^{-9} m

Explanation:

As we know by the principle of uncertainty that the product of uncertainty in position and uncertainty in momentum is given as

\Delta x \times \Delta P = \frac{h}{4\pi}

so here we know that

\Delta v = 0.01 \times 10^6 m/s

m = 9.11 \times 10^{-31} kg

so we have

\Delta x \times (9.11 \times 10^{-31})(0.01 \times 10^6) = \frac{6.26 \times 10^{-34}}{4\pi}

\Delta x = 5.47 \times 10^{-9} m

5 0
3 years ago
The distance between two corresponding parts of a wave is its
oksano4ka [1.4K]

Answer:

wavelenght

Explanation:

The wavelength is the spatial period of a wave, analogous to the temporal period, it is the distance between two consecutive points with maximum amplitude that are repeated in space . In the waves of the sea, the wavelength is easily observed in the separation between two consecutive ridges.

4 0
3 years ago
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8. two +1 C charges are separated by 3000m. What is the magnitude of the electric force between them?
Sidana [21]

Answer:

1000 N

Explanation:

The magnitude of the electrostatic force between two charged object is given by

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb constant

q1, q2 is the magnitude of the two charges

r is the distance between the two objects

Moreover, the force is:

- Attractive if the two forces have opposite sign

- Repulsive if the two forces have same sign

In this problem:

q_1=q_2=+1C are the two charges

r = 3000 m is their separation

Therefore, the electric force between the charges is:

F=(9\cdot 10^9)\frac{(1)(1)}{3000^2}=1000 N

8 0
3 years ago
The collision between a hammer and a nail can be considered to be approximately elastic. estimate the kinetic energy acquired by
Setler [38]

Here we can use momentum conservation as in this type of collision there is no external force on it

m_1v_{1i} + m_2v_{2i} = m_1 v_{1f} + m_2v_{2f}

now here we can say

m_1 = 10 g

v_{1i} = 0

m_2 = 550 g

v_{2i} = 3.5 m/s

now here we can say

10*0 + 550 * 3.5 = 10 v_{1f} + 550 v_{2f}

192.5 = v_{1f} + 55 v_{2f}

now by coefficient of restitution

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v_{1f} = v_{2f} + 3.5 = 3.375 + 3.5 = 6.875 m/s

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6 0
3 years ago
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