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trapecia [35]
3 years ago
5

The speed of all electromagnetic waves is 3.00 × 108 meters per second. What is the wavelength of an X-ray with a frequency of 1

.18 × 1018 Hz?
2.54 × 1026 meters
3.93 × 109 meters
2.54 × 10-10 meters
3.93 × 10-11 meters
Physics
2 answers:
Ierofanga [76]3 years ago
8 0
The answer is......2.54x10^-10......
Akimi4 [234]3 years ago
8 0

Explanation :

Given that,

The speed of all electromagnetic waves is, v=3\times 10^8\ m/s

Frequency of x-ray,\nu=1.18\times 10^{18}\ Hz

The speed of the wave is defined as the product of the frequency and the wavelength.

\lambda=\dfrac{v}{\nu}

\lambda=\dfrac{3\times 10^8}{1.18\times 10^{18}}

\lambda=2.54\times 10^{-10}\ m

So, the correct option is (c).

Hence, this is the required solution.

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3 years ago
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A group of humans traveling in space discover a habitable planet. They settle down there and start populating it. Their populati
storchak [24]

Answer:

10 years

Explanation:

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As it is mentioned there are no other factors affecting the growth rate, in 10years the planet will be filled to its carrying capacity.

6 0
2 years ago
Five moles of an ideal monatomic gas with an initial temperature of 121 ∘C expand and, in the process, absorb an amount of heat
liq [111]

Answer:

  T₂ ≈ 107.85∘C

Explanation:

The question didn't state if the volume is constant or not as such, we can apply the first law of thermodynamic

From the first law of thermodynamic,

ΔU =  Q - W

where ΔU = Internal Energy, Q = Quantity of heat absorbed, W = Amount of work done.

Q = 1200 J and W = 2020 J

∴ ΔU = 1200 -2020 = -820 J.

Using the ideal gas equation,

ΔU = 3/2nRΔT...................................equation 1

where n = number of moles, R = Molar gas constant, ΔT = Change in temperature = (T₂ - T₁).

Modifying equation 1,

ΔU = 3/2nR(T₂ -T₁)...............................equation 2.

making T₂ the subject of the relation in equation 2,

T₂ =  {2/3(ΔU)/nR}+T₁........................ equation 3

where T₁=121∘C, R= 8.314 J / mol, n=5 moles, ΔU=-820 J

Substituting these values into equation 3,

∴ T₂ ={ 2/3(-820)/(5×8.314)}+121

   T₂ = {2×(-820)/ (3×5×8.314)}+121  

   T₂={-1640/124.71}+ 121

   T₂ = {-13.151} + 121

 ∴T₂  = 121 - 13.151 = 107. 849∘C

    T₂ ≈ 107.85∘C

3 0
3 years ago
( Just answer 1 & 2) Please help! This is the last thing I have to do. I will mark brainliest asap!!
natima [27]

Answer:

1. Formula = distance/time

D= 112.0 meters, time =4 secs

Speed = d/t =112.0/4

= 28m/s

2.Formula = distance/time

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= 402.35m

Time = 15secs

Speed= d/t

= 402.35/15

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7 0
3 years ago
Pouvez vous m'aider dans ce devoir sil vous plait.​
ahrayia [7]

in english please

i don't understand actually

8 0
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