Answer:
A. 70 m OS the correct one
It only occurs when there is an electric current
(13.558 gm) · (1 L / 0.089 gm) = 152.34 L (rounded)
(fraction equal to ' 1 ') ^
Answer:
At the highest point the velocity is zero, the acceleration is directed downward.
Explanation:
This is a free-fall problem, in the case of something being thrown or dropped, the acceleration is equal to -gravity, so -9.80m/s^2. So, the acceleration is never 0 here.
I attached an image from my lecture today, I find it to be helpful. You can see that because of gravity the acceleration is pulled downwards.
At the highest point the velocity is 0, but it's changing direction and that's why there's still an acceleration there.
The first one. The E and B chatacteristic are perpendicular to eachother. The direction of the wave can be found by the right hand rule.