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2 years ago

Please help me!!!!! please explaining your answer = brainliest

Mathematics

2 answers:

jasenka [17]2 years ago

6 0

Answer:

42.39 sq.cm

Step-by-step explanation:

Ф = 135°

r = 6 cm

Area of the sector = $\frac{theta}{360}*\pi *r^{2}\\$

$= \frac{135}{360}* 3.14 *6 * 6\\\\= \frac{135}{10}*3.14\\\\= 27 * 1.57\\\\=42.39$

maksim [4K]2 years ago

3 0

The area of sector bounded by 135 ° arc is 42.42 cm ².

Step-by-step explanation:

<h3><u>Given</u> :-</h3>

Radius of the circle , r = 6 cm

Angle of the circle, θ = 135 °

Area of circle bounded by a 135 ° arc.

<h3><u>Solution</u> :-</h3>

We know that

$\small \sf \: Area \: of \: sector \: = \frac{θ}{360} \: \times \pi \times r {}^{2} \\$

Substitute the values of r and θ , we get

Area of sector =

$\small \sf \: Area \: of \: sector \: = \frac{135 °}{360} \: \times \pi \times {6cm}^{2}\\$

$\small \sf \: Area \: of \: sector \: = \frac{135°}{360} \: \times \frac{22}{7} \times 6cm \times 6cm \\ \\ \small \: \sf Area \: of \: circle \: = \frac{135}{360} \times \frac{22}{7} \times 36cm {}^{2} \\ \sf \: \: = \frac{135}{10} \times \frac{22}{7} \\ \sf \: = 42.42cm \: {}^{2}$

Therefore, The area of sector bounded by 135 ° arc is 42.42 cm ².

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Kari is adding a ribbon border to the edge of her kite. Two sides of the kite measure 9.5 inches each, and the other two sides m

Softa [21]

17.8 multiplied by 2 is 35.6
9.5 multiplied by 2 is 19
Now you take both of them and add them together.
35.6 + 19 = 54.6

Your answer should be 54.6 inches of ribbon.

Hope this helps.

8 0

3 years ago

The length of each side is quadrupled. How many times larger is the new area when compared to the original?

GaryK [48]

16 times larger is the new area when compared to the original.

Given that, the length of each side of the square is quadrupled.

We need to find how many times larger is the new area when compared to the original.

<h3>What is the area of a square?</h3>

A square is a closed two-dimensional shape with four equal sides and four equal angles. The four sides of the square form the four angles at the vertices. The sum of the total length of the sides of a square is its perimeter, and the total space occupied by the shape is the area of the square. The formula to calculate the area of a square is a².

Let the length of each side of the square be x.

Then the length of each side of the new square will be 4x.

Now, the area of the original square = x²

The area of the new square = (4x)² = 16x²

So, the new square = 16 × the original square

Therefore, 16 times larger is the new area when compared to the original.

To learn more about the area of a square visit:

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5 0

1 year ago

(04.01)

katrin [286]

The third one, 2 to the power of 5 over 6

√2 * 3√2

convert from radical form to exponent form to solve for the same root
( x^m/n = n√x^m )

2^(1/2) * 2^(1/3)
2^{3/6} * 2^{2/6} - find common denominator (6)
6√(2^3) * 6√(2^2) - convert back to radical form
6√(2^3 * 2^2)- combine

6<span>√(</span>2^5)
then convert to exponential form again
~ 2^5/6 ~

5 0

2 years ago

Which expression is equivalent to (5³) ‐²? (4 points)

miss Akunina [59]

Answer:

1. 2³ × 2² = (2 × 2 × 2) × (2 × 2) = 23+2 = 2⁵

2. 3⁴ × 3² = (3 × 3 × 3 × 3) × (3 × 3) = 34+2 = 3⁶

3. (-3)³ × (-3)⁴ = [(-3) × (-3) × (-3)] × [(-3) × (-3) × (-3) × (-3)]

= (-3)3+4

= (-3)⁷

4. m⁵ × m³ = (m × m × m × m × m) × (m × m × m)

= m5+3

= m⁸

Step-by-step explanation:

exponential law

3 0

2 years ago

To convert a quadratic from y = ax2 + bx + c form to vertex form, y = a(x - h)2+ k, you use the process of completing the square

ladessa [460]

Since we will be completing the square we need to isolate the x

y-5 = 2x^2 -4x

now we the coefficient of the x^2 to equal 1 so we take 2 as common factor

y-5 = 2(x^2 -2x)

now we'll make it perfect square by adding 2 to both sides

y-5+2=2(x^2-2x+1)

now simplify and convert the right side to squared expression

y-3 = 2(x-1)^2

now isolate the y

y = 2(x-1)^2 +3 that's it

5 0

3 years ago