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3 years ago

Which pair shows equivalent expressions?

Mathematics

2 answers:

Igoryamba3 years ago

5 0

Im pretty sure its a and c but if it cant be both of them then u or ur teacher probably wrote one of them wrong

umka21 [38]3 years ago

5 0

Answer:

its answer is A...as u see inA 10 can be divided by 2 and the answer comes 5 it is equivalent.

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A triangle has side lengths of 36 in, 27in, and 61 in. Classify it as acute, obtuse, or right.

Lady_Fox [76]

When given 3 triangle sides, to determine if the triangle is acute, right or obtuse:1) Square all 3 sides.36, 27, 61 1,296, 729, 3,721 2) Sum the squares of the 2 shortest sides.1,296 + 729 = 2,025

3) Compare this sum to the square of the 3rd side.2,025 < 3,721
if sum > 3rd side² Acute Triangleif sum = 3rd side² Right Triangleif sum < 3rd side² Obtuse TriangleTherefore, it is an Obtuse TriangleSource:http://www.1728.org/triantest.htm

7 0

3 years ago

3ab+2 x -a =2c a=2 b=3 c=7 True or False

ollegr [7]

Answer:

Step-by-step explanation:

8 0

2 years ago

Newton's law of cooling is:

Mnenie [13.5K]

Answer:

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

$\frac{du}{dt}= -k (u-T)$

We can reorder the expression like this:

$\frac{du}{u-T} = -k dt$

We can use the substitution $w = u-T$ and $dw =du$ so then we have:

$\frac{dw}{w} =-k dt$

IF we integrate both sides we got:

$ln |w| = -kt +C$

If we apply exponential in both sides we got:

$w = e^{-kt} *e^c$

And if we replace w = u-T we got:

$u(t)= T + C_1 e^{-kt}$

We can also express the solution in the following terms:

$u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}$

For this case we know that $k =-0.15 hr$ since w ehave a cooloing, $T_{i}= 70 F, T_{amb}=11F$ , we have this model:

$u(t) = (70-11) e^{-0.15t} +11$

And if we want that the temperature would be 32F we can solve for t like this:

$32 = 59 e^{-0.15 t} +11$

$21=59 e^{-0.15 t}$

$\frac{21}{59} = e^{-0.15 t}$

If we apply natural logs on both sides we got:

$ln (\frac{21}{59}) =-0.15 t$

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

7 0

3 years ago

60 is 30% of what number?

Phantasy [73]

Percent means parts out of 100
30%=30/100=3/10

'of' means multiply

60 is 30% of what translates to
60=3/10 times what
multiply both sides by 10/3
600/3=what
200=what
the number is 200

7 0

3 years ago

How do I find the values of these

skad [1K]

Since the triangles are similar, then 32 = x+7 those two angles are too
solve for "x"

now using proportions $\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{JK}{18}=\cfrac{12}{12+10}$

solve for JK

$\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{12}{12+10}=\cfrac{9}{9+KG}\implies 12(9+KG)=(22)9
\\\\\\
108+9KG=198$

solve for KG

the scale factor of the perimeter of both triangles is just the same as the ratio of the sides, or $\bf \cfrac{12}{12+10}$

3 0

3 years ago