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timama [110]
2 years ago
10

8. An object has a force applied. The object has a mass of 36 Kg and accelerates at 3.4 m/sec2. What is the force acting on the

object? *
a. 120.6 N
b. 126.9 N
c. 122.4 N
d. 118.3 N
Physics
1 answer:
satela [25.4K]2 years ago
7 0

Answer:

122.4

Explanation:

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Answer:

f Homework: Creating and Solving Linear Equations to Model Real World Problems Part I

he document will

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4 0
3 years ago
A 500N person stands 2.5m from a wall against which a horizontal beam is attached. The beam is 6m long and weighs 200N. A cable
Vinil7 [7]

PART A)

Here by force balance along Y direction

Tsin45  + F_y = 500 + 200

Force balance along X direction

Tcos45 = F_x

now by torque balance

Tsin45 (6) = 500 (2.5) + 200 (3)

T(4.24) = 1250 + 600

T = 436.3 N

PART B)

now from above equations

Tsin45 + F_y = 700

F_y = 391.5 N

F_x = Tcos45 = 308.5 N

now net reaction force of wall is given as

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5 0
3 years ago
In the chemical equation above, the small number after the O in 1202 represent —
Murrr4er [49]

Answer:

G.) The number atoms of that element in the molecule

Explanation:

F is incorrect because the coefficient represents the amount of one type of molecule, not the subscript

G is correct because subscripts represent how many atoms of that element are present in that single molecule

H is incorrect because energy is not represented in this simple type of equation

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7 0
2 years ago
in which kind of radioactive decay would the number of protons in the resulting nucleus be more than in the initial nucleus?
9966 [12]

Answer:

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2 years ago
A stone is launched straight up by a slingshot. Its initial speed is 19.6 m/s, and the stone is 1.50 m above the ground when lau
arlik [135]

Answer: a) 19.21m b) 3.92secs

Explanation:

a) Maximum height reached by the object is the height reached by an object before falling freely under gravity.

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U is the initial velocity = 19.6m/s

g is acceleration due to gravity = 10m/s²

Maximum Height = 19.6²/2(10)

H = 19.21m

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3 years ago
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