Ask question

Ask question

All categories

3 years ago

10

8. An object has a force applied. The object has a mass of 36 Kg and accelerates at 3.4 m/sec2. What is the force acting on the

object? *
a. 120.6 N
b. 126.9 N
c. 122.4 N
d. 118.3 N

1 answer:

satela [25.4K]3 years ago

7 0

Answer:

122.4

Explanation:

You might be interested in

Y'all I need this comon please give me a right answer

Natali [406]

It will be a virtual image that appears on the left side of the mirror

i hope this helps!

5 0

3 years ago

A child is riding a merry-go-round that has an instantaneous angular speed of 12 rpm. If a constant friction torque of 12.5 Nm i

sammy [17]

Answer:

$-0.25 rad/s^2$

Explanation:

The equivalent of Newton's second law for rotational motions is:

$\tau = I \alpha$

where

$\tau$ is the net torque applied to the object

I is the moment of inertia

$\alpha$ is the angular acceleration

In this problem we have:

$\tau = -12.5 Nm$ (net torque, with a negative sign since it is a friction torque, so it acts in the opposite direction as the motion)

$I=50.0 kg m^2$ is the moment of inertia

Solving for $\alpha$ , we find the angular acceleration:

$\alpha = \frac{\tau}{I}=\frac{-12.5 Nm}{50.0 kg m^2}=-0.25 rad/s^2$

3 0

3 years ago

A ball is thrown horizontally from the top of a building 22.3 m high. The ball strikes the ground at a point 127 m from the base

DochEvi [55]

Answer:

t = 2.13 s

Explanation:

given,

height of the building = 22.3 m

horizontal distance = 127 m

acceleration due to gravity = 9.8 m/s²

time for which ball is in motion = ?

using equation of motion

$s = u t + \dfrac{1}{2}gt^2$

initial velocity is zero

$s = \dfrac{1}{2}gt^2$

$t = \sqrt{\dfrac{2s}{g}}$

$t = \sqrt{\dfrac{2\times 22.3}{9.8}}$

t = √4.551

t = 2.13 s

8 0

3 years ago

The energy of a certain charged capacitor is 7 J. What is the new energy stored in that capacitor if its charge is decreased to

poizon [28]

Answer:

The new energy is 1/16 of the original energy

Explanation:

A capacitor is an electric device which is able to store charge when it is connected to a power supply.

The energy stored in a capacitor is given by the equation

$E=\frac{Q}{2C}$

where:

Q is the charge stored on the capacitor

C is the capacitance of the capacitor

For the capacitor in this problem, initially we have

E = 7 J (energy) when the charge stored is Q and the capacitance is C

Later, the charge is decreased to 1/4 of its original value, so the new charge is

$Q'=\frac{1}{4}Q$

Since the capacitance remains the same, the new energy is

$E'=\frac{(\frac{1}{4}Q)^2}{2C}=\frac{1}{16}\frac{Q^2}{2C}=\frac{1}{16}E$

Therefore, the new energy is 1/16 of the original energy.

6 0

3 years ago

What is the wavelength of an earthquake wave if it has a speed of 11 km/s and a frequency of 7 Hz?

Alex73 [517]

length = speed/freq

11/7km

6 0

3 years ago