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Dvinal [7]
2 years ago
5

How might the ability of magnets to attract certain metals relate to the crane?

Physics
1 answer:
stepan [7]2 years ago
7 0

Answer:

When the elctromagnet is ON, it picks up the iron pieces from the other scrap (copper, brass, bronze, aluminium, rubber, plastic, glass etc. that is non-magnetic. Then the crane moves to the designated spot where the iron is to be dumped. Then the electromagnet is OFF and the pieces drop - that is the beauty of soft magnetic materials like iron and electromagnetism. When the current is switched off the magnetism disappears and gravity takes over….

If we used a permanent magnet, the iron pieces would be picked up, but they would be stuck to the powerful magnet and removing them would be a tough task.

Explanation:

You might be interested in
The actual mechanical advantage of any machine is its__________divided by its________________
zaharov [31]

Answer: Load divided by it effort

Explanation:

Mechanical advantage of any machine is its load divided by its effort

4 0
3 years ago
Could someone please help me with this problem? I’m thinking that they both will have the same force because they have the same
Simora [160]
You would be correct
7 0
3 years ago
What is the component in a car engine that would detect the need for air?​
Ipatiy [6.2K]

Answer:

Control of air–fuel ratio

Oxygen sensors tell the ECU whether the engine is running rich (too much fuel or too little oxygen) or running lean (too much oxygen or too little fuel) as compared to ideal conditions (known as stoichiometric).

Explanation:

4 0
3 years ago
Determine the amount of work done by the engine of a car with a mass of 2500 kg when it accelerates from 45 mph to 65 mph. (Use
Y_Kistochka [10]

Answer:

amount of work done, W = 549.36 kJ

Given:

mass of a car engine, m = 2500 kg

initial velocity, u = 45 mph

final velocity, v = 65 mph

1 mile = 1609

Solution:

We know that 1 hour = 3600 s

Now, velocities in m/s are given as:

u = 45 mph = \frac{45\times 1609}{3600} = 20.11 m/s

v = 65 mph =  \frac{65\times 1609}{3600} = 29.05 m/s

Now, the amount of work done, W is given by the change in kinetic energy of the car and is given by:

W = \frac{1}{2}m\Delta v^{2}

W = \frac{1}{2}m\times (v^{2} - u^{2})

W = \frac{1}{2}2500\times (29.05^{2} - 20.11^{2})

W = 549.36 kJ

3 0
3 years ago
easy bio A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 438 N and have a center of
goblinko [34]

Answer:

1.034 m above the floor

Explanation:

The location of center of body for a compound body, when the weights are given is calculated as:

\bar x = \frac{W_1x_1+W_2x_2+W_3x_3+W_4x_4+W_5x_5+.......+Wnx_n}{W_1+W_2W_3W_4W_5+.....+W_n}

where,

\bar x is the center of gravity of the entire body

W = weight of the individual body

x = center of gravity of the individual body

Thus on substituting the values we get,

\bar x = \frac{438\times 1.28+144\times 0.760+87\times 0.250}{438+144+87}

or

\bar x = \frac{691.83}{669}

or

\bar x =1.034m

Hence, <u>the center of gravity of the entire body lies </u><u>1.034 m</u><u> </u><u>above the floor</u>

6 0
3 years ago
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