Answer:
Explanation:
The bike's acceleration can be found by using the following suvat equation:
where
v is the final velocity of the bike
u is the initial velocity
a is the acceleration
s is the distance covered
For the bike in the problem,
u = 0
v = 7 m/s
d = 40 m
Solving the equation for a, we find the acceleration:
≈40.8kg
this is to take up space
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
