Generally living things become fossils. Plants, animals, etc.
Explanation:
(a). First of all, we calculate the number of atoms per cm^{3}, and by taking into account that each atom contributes with one free electron we have
(b)
(c)
I hope this is useful for you
P.D please change 1.628 (the diameter) by 0.814(the radius) in the calculation
:)
Answer:
The correct answer is
p = p₁ + p₂
Explanation:
Newton's second law states that force = the change of momentum produced therefore since the collision is inelstic then the change of momentum of each car is p₁ and p₂ and the force of the collition is proportional to p₁ + p₂ that is
F ∝ p₁ + p₂ and since force is directly proportional to p we have
p = p₁ + p₂
The new frequency of oscillation when the car bounces on its springs is 0.447 Hz
<h3>Frequency of oscillation of spring</h3>
The frequency of oscillation of the spring is given by f = (1/2π)√(k/m) where
- k = spring constant and
- m = mass on spring
Now since k is constant, and f ∝ 1/√m.
So, we have f₂/f₁ = √(m₁/m₂) where
- f₁ = initial frequency of spring = 1.0 Hz,
- m₁ = mass of driver,
- f₂ = final frequency of spring and
- m₂ = mass on spring when driver is joined by 4 friends = 5m₁
So, making f₂ subject of the formula, we have
f₂ = [√(m₁/m₂)]f₁
Substituting the values of the variables into the equation, we have
f₂ = [√(m₁/m₂)]f₁
f₂ = [√(m₁/5m₁)]1.0 Hz
f₂ = [√(1/5)]1.0 Hz
f₂ = 1.0 Hz/√5
f₂ = 1.0 Hz/2.236
f₂ = 0.447 Hz
So, the new frequency of oscillation when the car bounces on its springs is 0.447 Hz
Learn more about frequency of oscillation of spring here:
brainly.com/question/15318845
Answer:
<em>The frequency changes by a factor of 0.27.</em>
<em></em>
Explanation:
The frequency of an object with mass m attached to a spring is given as
=
where is the frequency
k is the spring constant of the spring
m is the mass of the substance on the spring.
If the mass of the system is increased by 14 means the new frequency becomes
=
simplifying, we have
=
=
if we divide this final frequency by the original frequency, we'll have
==> ÷
==> x
==> 1/3.742 = <em>0.27</em>